日期范围阵列，不包括星期日&在PHP度假 [英] Date range array excluding the Sunday & the holiday in PHP

问题描述

我有一个函数返回数组中两个日期之间的所有日期，但是我需要排除该数组中的星期日。

  public function dateRange（$ first，$ last，$ step ='+1 day'，$ format ='d / m / Y'）{
 $ dates = array（）; 
 $ current = strtotime（$ first）; 
 $ last = strtotime（$ last）; 
 while（$ current< = $ last）{
 $ dates [] = date（$ format，$ current）; 
 $ current = strtotime（$ step，$ current）; 
} 
 return $ dates; 
} 
  

排除星期日后，我有一张表，我将存储一些日期，我也需要从数组中排除这些日期。

喜欢，如果我输入日期范围为01-05-2012（DD-MM-YYYY）到10 -05-2012，
06-05-2012将是星期日&日期01-05-2012& 08-05-2012将在上面提到的表中，
最终出来应该是这样，

  02-05-2012 
 03-05-2012 
 04-05-2012 
 05-05-2012 
 07-05-2012 
 09-05- 2012 
 10-05-2012 
  

如何在PHP中执行此操作？
我尝试了一些但找不到正确的方法。

解决方案

对于星期日部分： / p>

  public function dateRange（$ first，$ last，$ step ='+1 day'，$ format ='d / m / Y'）{
 $ dates = array（）; 
 $ current = strtotime（$ first）; 
 $ last = strtotime（$ last）; 
 while（$ current< = $ last）{
 if（date（D，$ current）！=Sun）
 $ dates [] = $ current）; 
 $ current = strtotime（$ step，$ current）; 
} 
 return $ dates; 
} 
  

假期部分：

首先，您需要将日期加载到某种数组中，然后循环遍历每个日期的数组，并检查它们是否匹配。

I have a function which returns all the dates between two dates in an array, But I need to exclude Sundays in that array.

public function dateRange($first, $last, $step = '+1 day', $format = 'd/m/Y' ) { 
    $dates = array();
    $current = strtotime($first);
    $last = strtotime($last);
    while( $current <= $last ) { 
        $dates[] = date($format, $current);
        $current = strtotime($step, $current);
    }
    return $dates;
}

After excluding the Sundays, I have a table where I will be storing some dates, I need to exclude those dates from the array too.

like, If I enter the date range as 01-05-2012(DD-MM-YYYY) to 10-05-2012, The 06-05-2012 will be Sunday & the date 01-05-2012 & 08-05-2012 will be in the table which I mentioned above, The final out put should be like,

02-05-2012
03-05-2012
04-05-2012
05-05-2012
07-05-2012
09-05-2012
10-05-2012

How to do this in PHP ? I tried some but couldn't find the right way to do it.

解决方案

For the Sundays part:

public function dateRange($first, $last, $step = '+1 day', $format = 'd/m/Y' ) { 
    $dates = array();
    $current = strtotime($first);
    $last = strtotime($last);
    while( $current <= $last ) { 
        if (date("D", $current) != "Sun")
            $dates[] = date($format, $current);
        $current = strtotime($step, $current);
    }
    return $dates;
}

For the holidays part:

First you need to load the dates into some kind of array and then loop through the array for each of your dates and check if they match.

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