日期之间的月份和日期 [英] Javascript Months and Days between dates

问题描述

我想知道有没有人有JavaScript函数可以返回两个日期之间的月份和日期？例如，如果通过01/01/2013和03/01/2015（UK Date format）将返回24个月2天。我有几个月的时间，但我正在努力与日子。我的表单上有两个日期字段，以dd / mm / yyyy格式。这是我到目前为止的代码：

  function calculateDateDifference（）{
 var startDateValue = document.forms [0] .StartDate.value; 
 var endDateValue = document.forms [0] .EndDate.value; 
 
 var startDateArray = startDateValue.split（/）; 
 var endDateArray = endDateValue.split（/）; 
 
 var startDate = new Date（startDateArray [2]，startDateArray [1]，startDateArray [0]）; 
 var endDate = new Date（endDateArray [2]，endDateArray [1]，endDateArray [0]）; 
 
 var diffYears = endDate.getFullYear（） -  startDate.getFullYear（）; 
 var diffMonths = endDate.getMonth（） -  startDate.getMonth（）; 
 var diffDays = endDate.getDate（） -  startDate.getDate（）; 
 
 var months =（（diffYears * 12）+ diffMonths）; 
 if（diffDays< 0）{
 months = months-1; 
} 
 alert（months +months）; 
} 
  

提前感谢
Niall。

解决方案

感谢@Zazerat在这篇文章

我已经提出了一个解决方案。 @Jazerat提供了一个JSDate的缩减版本，我可以轻松地在Date日期进行月度调整。这里是最终的代码：

  Date.isLeapYear = function（year）{
 return（（（year％4 = == 0）&&（年％100！== 0））||（年％400 === 0））; 
}; 
 
 Date.getDaysInMonth = function（year，month）{
 return [31，（Date.isLeapYear（year）？29：28），31，30，31，30，31， 31，30，31，30，31] [月]; 
}; 
 
 Date.prototype.isLeapYear = function（）{
 var y = this.getFullYear（） 
 return（（（y％4 === 0）&（y％100！== 0））||（y％400 === 0））; 
}; 
 
 Date.prototype.getDaysInMonth = function（）{
 return Date.getDaysInMonth（this.getFullYear（），this.getMonth（））; 
}; 
 
 Date.prototype.addMonths = function（value）{
 var n = this.getDate（）; 
 this.setDate（1）; 
 this.setMonth（this.getMonth（）+ value）; 
 this.setDate（Math.min（n，this.getDaysInMonth（）））; 
返回这个; 
}; 
 
 function daysInMonth（month，year）{
 return new Date（year，month，0）.getDate（）; 
} 
 
 
函数calculateLeasePeriod（）{
 
 var startDateValue = document.forms [0] .StartDate.value; 
 var endDateValue = document.forms [0] .EndDate.value; 
 
 if（endDateValue！=&& startDateValue！=）{
 
 var startDateArray = startDateValue.split（/）; 
 var endDateArray = endDateValue.split（/）; 
 
 var startDate = new Date（startDateArray [2]，startDateArray [1]，startDateArray [0]）; 
 var endDate = new Date（endDateArray [2]，endDateArray [1]，endDateArray [0]）; 
 
 var diffYears = endDate.getFullYear（） -  startDate.getFullYear（）; 
 var diffMonths = endDate.getMonth（） -  startDate.getMonth（）; 
 var diffDays = endDate.getDate（） -  startDate.getDate（）; 
 
 var months =（（diffYears * 12）+ diffMonths）; 
 if（diffDays< 0）{
 months = months-1; 
 var adjStartDate = startDate.addMonths（months）; 
 diffDays = endDate.getDate（） -  adjStartDate.getDate（）; 
 if（diffDays< 0）{
 diffDays = daysInMonth（adjStartDate.getMonth（），adjStartDate.getYear（））+ diffDays; 
} 
} 
 
 $（＃PrimaryLeasePeriod）。html（months +months and+ diffDays +days）; 
 
} else {
 $（＃PrimaryLeasePeriod）。html（）; 
} 
} 
  

我希望有人找到这个有用的！ >

I'm wondering if anyone has a JavaScript function to return the number of months and days between 2 dates? For example, if passed 01/01/2013 and 03/01/2015 (UK Date format) It would return 24 Months 2 Days. I have the months part, but I'm struggling with the days piece. There are 2 date fields on my form on dd/mm/yyyy format. here's the code I have so far:

function calculateDateDifference(){
var startDateValue=document.forms[0].StartDate.value;
var endDateValue=document.forms[0].EndDate.value;

var startDateArray=startDateValue.split("/");
var endDateArray=endDateValue.split("/");

var startDate= new Date(startDateArray[2], startDateArray[1], startDateArray[0]);
var endDate= new Date(endDateArray[2], endDateArray[1], endDateArray[0]);

var diffYears = endDate.getFullYear()-startDate.getFullYear();
var diffMonths = endDate.getMonth()-startDate.getMonth();
var diffDays = endDate.getDate()-startDate.getDate();

var months = ((diffYears*12) + diffMonths);
if (diffDays<0){
    months=months-1;
    }
alert(months + " months");
}

Thanks in advance, Niall.

解决方案

Thanks to the answer by @Zazerat on this post

I have come up with a solution. @Jazerat provided a cut down version of JSDate which I included to easily allow for month adjustment on a Date. Here's the final code:

    Date.isLeapYear = function (year) { 
    return (((year % 4 === 0) && (year % 100 !== 0)) || (year % 400 === 0)); 
};

Date.getDaysInMonth = function (year, month) {
    return [31, (Date.isLeapYear(year) ? 29 : 28), 31, 30, 31, 30, 31, 31, 30, 31, 30, 31][month];
};

Date.prototype.isLeapYear = function () { 
    var y = this.getFullYear(); 
    return (((y % 4 === 0) && (y % 100 !== 0)) || (y % 400 === 0)); 
};

Date.prototype.getDaysInMonth = function () { 
    return Date.getDaysInMonth(this.getFullYear(), this.getMonth());
};

Date.prototype.addMonths = function (value) {
    var n = this.getDate();
    this.setDate(1);
    this.setMonth(this.getMonth() + value);
    this.setDate(Math.min(n, this.getDaysInMonth()));
    return this;
};

function daysInMonth(month,year) {
    return new Date(year, month, 0).getDate();
}


function calculateLeasePeriod(){

var startDateValue=document.forms[0].StartDate.value;
var endDateValue=document.forms[0].EndDate.value;

if (endDateValue!="" && startDateValue!=""){

    var startDateArray=startDateValue.split("/");
    var endDateArray=endDateValue.split("/");

    var startDate= new Date(startDateArray[2], startDateArray[1], startDateArray[0]);
    var endDate= new Date(endDateArray[2], endDateArray[1], endDateArray[0]);

    var diffYears = endDate.getFullYear()-startDate.getFullYear();
    var diffMonths = endDate.getMonth()-startDate.getMonth();
    var diffDays = endDate.getDate()-startDate.getDate();

    var months = ((diffYears*12) + diffMonths);
    if (diffDays<0){
        months=months-1;
        var adjStartDate = startDate.addMonths(months);
        diffDays = endDate.getDate()-adjStartDate.getDate();
        if (diffDays<0){
            diffDays=daysInMonth(adjStartDate.getMonth(), adjStartDate.getYear())+ diffDays;
            }
        }

    $("#PrimaryLeasePeriod").html(months + " months and " + diffDays + " days");

    }else{
        $("#PrimaryLeasePeriod").html("");
    }
}

I hope someone else finds this useful!

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