在JavaScript中的两倍之间的差异 [英] Difference Between two times as percentage in javascript

问题描述

例如：

  var timeone =01:23:00; // time elapsed 
 var timetwo =07:34:00; //总时间
  

那么我如何计算总和&消耗时间并取出百分比？

更新

尝试这个，但在控制台我看到NaN

  var TimeLeft = Date.parse（TimeLft.text ））/ 100; 
 console.log（TimeLeft）; 
 var Totaltime = Date.parse（DealTotalTm）/ 100; 
 console.log（Totaltime）; 
 var percentChange =（TimeLeft / Totaltime）* 100; 
 
 console.log（percentChange）; 
  

解决方案

由于您正在使用 / em>而不是一天中的时间，那么我建议避免使用 Date 对象。它的目的是为了不同的目的。

如果您可以保证输入在小时：分钟：秒格式您指定的，然后简单地拆分部分，以将总秒数计算为单个整数。然后，您可以划分它们以获得百分比，如下所示：

  function totalSeconds（time）{
 var parts = time.split（'：'）; 
返回零件[0] * 3600 +零件[1] * 60 +零件[2]; 
} 
 
 var timeone =01:23:00; // time elapsed 
 var timetwo =07:34:00; //总时间
 var pct =（100 * totalSeconds（timeone）/ totalSeconds（timetwo））。toFixed（2）; 
  

我已将结果固定为两位小数，但您可以根据需要进行调整。 p>

jsFiddle here 。

example say :

var timeone = "01:23:00"; // time elapsed
var timetwo = "07:34:00"; // total time 

then how can i calculate the difference between total & elapsed time and take out the percentage of it ?

Update

Tried this but in console I see "NaN"

var TimeLeft =  Date.parse(TimeLft.text())/100;
            console.log(TimeLeft);
            var Totaltime = Date.parse(DealTotalTm)/100;
            console.log(Totaltime);
            var percentChange = (TimeLeft/Totaltime)*100;

            console.log(percentChange);

解决方案

Since you are working with elapsed time and not time of day, then I recommend avoiding the Date object. It's intended for a different purpose.

If you can guarantee the inputs are in the hour:minute:second format that you specified, then simply split the parts to calculate the total seconds as a single integer. You can then divide them to obtain the percentage, like this:

function totalSeconds(time){
    var parts = time.split(':');
    return parts[0] * 3600 + parts[1] * 60 + parts[2];
}

var timeone = "01:23:00"; // time elapsed
var timetwo = "07:34:00"; // total time 
var pct = (100 * totalSeconds(timeone) / totalSeconds(timetwo)).toFixed(2);

I've fixed the results to two decimal places, but you can adjust if you like.

jsFiddle here.

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