php date（'d'）连续两天计算相同的输出 [英] php date('d') calculates same output for two consecutive days

问题描述

我正在通过PHP构建一个日历，并且这样做的方式在几天内被写入两次。

我复制了这个小脚本中的行为：

 <？php 
 // 
 //定义从$ b $开始的日期b // 
 $ d = 26; 
 $ m = 10; 
 $ y = 2013; 
 date_default_timezone_set（'CET'）; 
 $ time = mktime（0，0，0，$ m，$ d，$ y）; 
 
 // 
 //计算10年
 // 
（$ i = 0; $ i <3650; $ i ++）{
 $ tomorrowTime = $ time +（60 * 60 * 24）; 
 
 // 
 //如果第二天有相同的日期（'d'）结果$ echo 
 // 
 if（date（'d' $ time）== date（'d'，$ tomorrowTime））{
 echo date（'dm-Y'，$ time）计算了两次... \\\
; 
} 
 
 $ time = $ tomorrowTime; 
} 
 
？> 
  

这是我得到的：

  27-10-2013计算了两次... 
 26-10-2014计算了两次... 
 25-10-2015计算了两次... 
 30-10-2016计算了两次... 
 29-10-2017计算了两次... 
 28-10-2018计算了两次... 
 27计算了两个... ... 
 25-10-2020计算了两次... 
 31-10-2021计算了两次... 
 30-10-2022被计算两次... 
  

当我定义 $ time as 0（unix epoch），我没有得到相同的行为。
使用 mktime（）有什么问题吗？
还是11月只是尴尬？

干杯，
Jeroen

解决方案

此语句应该更好地防范闰秒等等：

  $ tomorrowTime = strtotime（'+ 1天，$时间）; 
  

I'm building a calendar through PHP and the way I'm doing this results on some days being written twice.

I replicated the behaviour in this little script:

<?php
//
// define a date to start from
//
$d = 26;
$m = 10;
$y = 2013;
date_default_timezone_set('CET');
$time = mktime(0, 0, 0, $m, $d, $y);

//
// calculate 10 years
//
for($i=0;$i<3650;$i++){ 
  $tomorrowTime = $time + (60 * 60 * 24);

  //
  // echo date if the next day has the same date('d') result
  //
  if(date('d',$time)==date('d',$tomorrowTime)){
    echo date('d-m-Y',$time)." was calculated twice... \n";
  }

  $time = $tomorrowTime;
}

?>

This is what I get:

27-10-2013 was calculated twice... 
26-10-2014 was calculated twice... 
25-10-2015 was calculated twice... 
30-10-2016 was calculated twice... 
29-10-2017 was calculated twice... 
28-10-2018 was calculated twice... 
27-10-2019 was calculated twice... 
25-10-2020 was calculated twice... 
31-10-2021 was calculated twice... 
30-10-2022 was calculated twice... 

When I define $time as 0 (unix epoch), I don't get the same behaviour. Is there something wrong with using mktime()? Or is November just being awkward?

Cheers, Jeroen

解决方案

This statement should guard better against leap seconds and such:

$tomorrowTime = strtotime('+1 days', $time);

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