从shell脚本中的字符串中提取日期 [英] Extract date from string in shell script

问题描述

我想获取一个带有shell脚本的字符串的日期，例如：

  dddddddddddddansdpaojhndpaosdjnad 
 ddddddddddddddansdpaojhndpaosdjnad 
 dddddddddddddansdpaojhndpaosdjnad 
 dddddddddddddddansdpaSun Apr 07 10:38:34 EEST 2013jnad 
 dddddddddddddansdpaojhndpaosdjnad 
  

如何用shell脚本提取字符串中的日期？

解决方案

我不知道您的示例文本真的反映了您的真实数据。而我认为 EEST 是一个打字错误？如果您按照以下示例进行工作：

  dddddddddddddansdpaojhndpaosdjnad 
 dddddddddddddansdpaojhndpaosdjnad 
 dddddddddddddansdpaojhndpaosdjnad 
 dddddddddddddddansdpaSun Apr 07 10:38:34 EEST 2013jnad 
 dddddddddddddansdpaojhndpaosdjnad 
  

这一行应该做这个工作： p>

  grep -o'[AZ]。* [0-9]'
  pre> 
 
 
例如：
  kent $ echodddddddddddddansdpaojhndpaosdjnad 
 dddddddddddddansdpaojhndpaosdjnad 
 dddddddddddddansdpaojhndpaosdjnad 
 dddddddddddddddansdpaSun Apr 07 10:38:34 EEST 2013jnad 
 dddddddddddddansdpaojhndpaosdjnad| grep -o'[AZ]。* [0-9]'
 Sun Apr 07 10:38:34 EEST 2013 
  
 
I want to get a date which is in a string with shell script for an example:
    dddddddddddddddansdpaojhndpaosdjnad
    dddddddddddddddansdpaojhndpaosdjnad
    dddddddddddddddansdpaojhndpaosdjnad
    dddddddddddddddansdpaSun Apr 07 10:38:34 EEST 2013jnad
    dddddddddddddddansdpaojhndpaosdjnad
How I can extract a date wich is in a string with shell script?
解决方案
I don't know if your example text is really reflecting your real data. And I think the EEST is a typo? If work on the example you gave:
dddddddddddddddansdpaojhndpaosdjnad
dddddddddddddddansdpaojhndpaosdjnad
dddddddddddddddansdpaojhndpaosdjnad
dddddddddddddddansdpaSun Apr 07 10:38:34 EEST 2013jnad
dddddddddddddddansdpaojhndpaosdjnad
this line should do the job:
grep -o '[A-Z].*[0-9]'
for example:
kent$  echo "    dddddddddddddddansdpaojhndpaosdjnad
    dddddddddddddddansdpaojhndpaosdjnad
    dddddddddddddddansdpaojhndpaosdjnad
    dddddddddddddddansdpaSun Apr 07 10:38:34 EEST 2013jnad
    dddddddddddddddansdpaojhndpaosdjnad"|grep -o '[A-Z].*[0-9]'
Sun Apr 07 10:38:34 EEST 2013


                        
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