以小时和分钟计算两列之间的 pandas DataFrame时间差 [英] Calculate Pandas DataFrame Time Difference Between Two Columns in Hours and Minutes

问题描述

当我尝试添加新列差异以找到使用

I have two columns from and to date in a dataframe

b
$ b

when I try add new column diff with to find the difference between two date using

df['diff'] = df['todate'] - df['fromdate']

如果超过24小时，我可以在几天内得到差异列。

I get the diff column in days if more than 24 hours.

2014-01-24 13:03:12.050000,2014-01-26 23:41:21.870000,"2 days, 10:38:09.820000"
2014-01-27 11:57:18.240000,2014-01-27 15:38:22.540000,03:41:04.300000
2014-01-23 10:07:47.660000,2014-01-23 18:50:41.420000,08:42:53.760000

如何仅在几分钟内转换我的结果，忽略几天甚至几秒钟。

How do I convert my results only in hours and minutes ignoring days and even seconds.

推荐答案

熊猫时间戳差异返回一个datetime.timedelta对象。这可以通过使用* as_type *方法很容易地转换成小时，像这样

Pandas timestamp differences returns a datetime.timedelta object. This can easily be converted into hours by using the *as_type* method, like so

import pandas
df = pandas.DataFrame(columns=['to','fr','ans'])
df.to = [pandas.Timestamp('2014-01-24 13:03:12.050000'), pandas.Timestamp('2014-01-27 11:57:18.240000'), pandas.Timestamp('2014-01-23 10:07:47.660000')]
df.fr = [pandas.Timestamp('2014-01-26 23:41:21.870000'), pandas.Timestamp('2014-01-27 15:38:22.540000'), pandas.Timestamp('2014-01-23 18:50:41.420000')]
(df.fr-df.to).astype('timedelta64[h]')

0    58
1     3
2     8
dtype: float64

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