如何解析目标C中的ISO-8601持续时间? [英] How to parse an ISO-8601 duration in Objective C?
本文介绍了如何解析目标C中的ISO-8601持续时间?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我正在寻找一种简单的方法来解析在Objective C中包含ISO-8601 持续时间的字符串。结果应该是像 NSTimeInterval
。
I'm looking for an easy way to parse a string that contains an ISO-8601 duration in Objective C. The result should be something usable like a NSTimeInterval
.
ISO-8601持续时间的一个例子: P1DT13H24M17S
,这意味着1天, 13小时24分17秒。
An example of an ISO-8601 duration: P1DT13H24M17S
, which means 1 day, 13 hours, 24 minutes and 17 seconds.
推荐答案
如果您确切知道要获得哪些字段,可以使用一个调用 sscanf()
:
If you know exactly which fields you'll be getting, you can use one invocation of sscanf()
:
const char *stringToParse = ...;
int days, hours, minutes, seconds;
NSTimeInterval interval;
if(sscanf(stringToParse, "P%dDT%dH%dM%sS", &days, &hours, &minutes, &seconds) == 4)
interval = ((days * 24 + hours) * 60 + minutes) * 60 + seconds;
else
; // handle error, parsing failed
如果任何字段可能被省略,您需要在你的解析中有点聪明,例如:
If any of the fields might be omitted, you'll need to be a little smarter in your parsing, e.g.:
const char *stringToParse = ...;
int days = 0, hours = 0, minutes = 0, seconds = 0;
const char *ptr = stringToParse;
while(*ptr)
{
if(*ptr == 'P' || *ptr == 'T')
{
ptr++;
continue;
}
int value, charsRead;
char type;
if(sscanf(ptr, "%d%c%n", &value, &type, &charsRead) != 2)
; // handle parse error
if(type == 'D')
days = value;
else if(type == 'H')
hours = value;
else if(type == 'M')
minutes = value;
else if(type == 'S')
seconds = value;
else
; // handle invalid type
ptr += charsRead;
}
NSTimeInterval interval = ((days * 24 + hours) * 60 + minutes) * 60 + seconds;
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