在Python中将年/月/日转换为年 [英] Convert Year/Month/Day to Day of Year in Python

问题描述

我使用Pythondatetime模块，即：

I'm using the Python "datetime" module, i.e.:

>>> import datetime
>>> today = datetime.datetime.now()
>>> print today
2009-03-06 13:24:58.857946

我想计算闰年敏感的年份。例如oday（2009年3月6日）是2009年第65天。这里是基于Web的DateTime计算器。

and I would like to compute the day of year that is sensitive of leap years. e.g. oday (March 6, 2009) is the 65th day of 2009. Here's web-based DateTime calculator.

无论如何，我看到两个选项：

Anyway, I see a two options:

1. 创建一个number_of_days_in_month array = [31，28，...]，决定是否是闰年，手动总结日期

1. Create a number_of_days_in_month array = [31, 28, ...], decide if it's a leap year, manually sum up the days

使用datetime.timedelta猜测然后二进制搜索一年中的正确日期：

Use datetime.timedelta to make a guess & then binary search for the correct day of year:

。

>>> import datetime
>>> YEAR = 2009
>>> DAY_OF_YEAR = 62
>>> d = datetime.date(YEAR, 1, 1) + datetime.timedelta(DAY_OF_YEAR - 1)

这些都觉得很笨重我有一种直觉，有一种更计数的计算方式是一年中的一年。任何想法/建议？

These both feel pretty clunky & I have a gut feeling that there's a more "Pythonic" way of calculating day of year. Any ideas/suggestions?

推荐答案

有一个非常简单的解决方案：

There is a very simple solution:

day_of_year = datetime.now().timetuple().tm_yday

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