从NOW（）函数获取相对日期 [英] Get relative date from the NOW() function

问题描述

我尝试从MySQL NOW（）函数获取相对日期和时间（例如2秒前，3天前，12月31日）。 ）但我不知道怎么样有任何想法吗？非常感谢你！

I try to get the relative date and time from the MySQL NOW() function, (like 2 seconds ago, 3 days ago, on the 31st of december...) but I have no idea how! Any ideas? Thank you so much!

推荐答案

使用 TIMESTAMPDIFF（） 功能。参见示例：

Use TIMESTAMPDIFF() function. See example:

SELECT
    TIMESTAMPDIFF(SECOND, `stamp_column`, NOW()) as `seconds`
FROM
    `YourTable`

或使用这个存储的函数：

Or use this stored function:

CREATE FUNCTION `PassedSince`(`stamp` TIMESTAMP)
RETURNS VARCHAR(100)
DETERMINISTIC
BEGIN
DECLARE `result` VARCHAR(100) DEFAULT '';
DECLARE `seconds`, `minutes`, `hours`, `days` INT;

SET `seconds` = TIMESTAMPDIFF(SECOND, `stamp`, NOW());

SET `days`    = `seconds` DIV (24 * 60 * 60);
SET `seconds` = `seconds` MOD (24 * 60 * 60);

IF `days` > 0
THEN SET `result` = CONCAT(`result`, `days`, ' Days ');
END IF;

SET `hours`   = `seconds` DIV (60 * 60);
SET `seconds` = `seconds` MOD (60 * 60);

IF `hours` > 0
THEN SET `result` = CONCAT(`result`, `hours`, ' Hours ');
END IF;

SET `minutes` = `seconds` DIV 60;
SET `seconds` = `seconds` MOD 60;

IF `minutes` > 0
THEN SET `result` = CONCAT(`result`, `minutes`, ' Minutes ');
END IF;

IF `seconds` > 0
THEN SET `result` = CONCAT(`result`, `seconds`, ' Seconds ');
END IF;

RETURN TRIM(`result`);
END

查询：

SELECT
    `PassedSince`('2013-06-19 08:00') as `result`
UNION ALL
SELECT
    `PassedSince`('2013-01-01 00:00')

显示：

result
--------------------------------------
1 Hours 20 Minutes 55 Seconds
169 Days 9 Hours 20 Minutes 55 Seconds

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