四舍五入到最近四分之一小时 [英] Rounding time to nearest quarter hour

问题描述

我有一个POSIXct值的向量，我想把它们四舍五入到最近。我不在乎那一天。如何将值转换为小时和分钟？

例如，我想要的值

<$ p $

$ b

 20:45
  

解决方案

像

 格式（strptime 90％，％H：％M）+ round（as.numeric（your.time）/ 900）* 900，％H：％M 
  

将工作

I have a vector of POSIXct values and I would like to round them to the nearest quarter hour. I don't care about the day. How do I convert the values to hours and minutes?

For example, I would like the value

"2012-05-30 20:41:21 UTC"

to be

"20:45"

解决方案

something like

format(strptime("1970-01-01", "%Y-%m-%d", tz="UTC") + round(as.numeric(your.time)/900)*900,"%H:%M")

would work

这篇关于四舍五入到最近四分之一小时的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！