如何在python中计算两个日期之间的差异 [英] How to calculate difference between two dates in weeks in python

问题描述

我正在计算一年中的几个星期的两个日期之间的差异。我可以得到datetime对象，并获取日期等，但不能得到周数。当然，我不能减去日期，因为周末不能保证。

I'm trying to calculate the difference between two dates in "weeks of year". I can get the datetime object and get the days etc but not week numbers. I can't, of course, subtract dates because weekends can't be ensured with that.

我尝试使用 d1.isocalendar（）[1] 并减去 d2.isocalendar（）[1] 但问题是 isocalendar（）[1] 返回 2012 作为第1周（据说是正确的），但这意味着我的逻辑不能跨过这个日期。

I tried getting the week number using d1.isocalendar()[1] and subtracting d2.isocalendar()[1] but the issue is that isocalendar()[1] returns December 31, 2012 as week 1 (which supposedly is correct) but that means my logic cannot span over this date.

以下是我的完整代码：

def week_no(self):
    ents = self.course.courselogentry_set.all().order_by('lecture_date')
    l_no = 1
    for e in ents:
        if l_no == 1: 
             starting_week_of_year = e.lecture_date.isocalendar()[1] # get week of year
             initial_year = e.lecture_date.year   
        if e == self: 
            this_year = e.lecture_date.year
            offset_week = (this_year - initial_year) * 52
            w_no = e.lecture_date.isocalendar()[1] - starting_week_of_year + 1 + offset_week
            break 
        l_no += 1
    return w_no  

有了这段代码，2012年12月31日的演讲结束了是-35。

With this code, the lecture on Dec 31, 2012 ends up being -35.

推荐答案

在相应日期的几周内计算星期一之间的星期差异如何？在以下代码中， monday1 是 d1 （同一周）之前的星期一：

How about calculating the difference in weeks between the Mondays within weeks of respective dates? In the following code, monday1 is the Monday on or before d1 (the same week):

from datetime import datetime, timedelta

monday1 = (d1 - timedelta(days=d1.weekday()))
monday2 = (d2 - timedelta(days=d2.weekday()))

print 'Weeks:', (monday2 - monday1).days / 7

如果两个日期下降一周， 0 1 周等。

Returns 0 if both dates fall withing one week, 1 if on two consecutive weeks, etc.

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