PHP - 确定日期是否在将来使用DateTime对象 [英] PHP - Determine if the date is in the future using DateTime Objects

问题描述

我正在尝试确定日期是否在将来，或者不使用 DateTime 对象，但总是回到正面：

I am trying to determine whether a date is in the future or not using DateTime objects but it always comes back positive:

$opening_date = new DateTime($current_store['openingdate']);
$current_date = new DateTime();
$diff = $opening_date->diff($current_date);
echo $diff->format('%R'); // +

if($diff->format('%R') == '+' && $current_store['openingdate'] != '0000-00-00' && $current_store['openingdate'] !== NULL) {
    echo '<img id="openingsoon" src="/img/misc/openingsoon.jpg" alt="OPENING SOON" />';
}

问题是它总是积极的，所以图像显示何时不应该

The problem is it's always positive so the image shows when it shouldn't be.

我一定是在做一些愚蠢的事情，但是它是什么驱使我疯狂！

I must be doing something stupid, but what is it, it's driving me insane!

推荐答案

比你想象的容易得多您可以与 DateTime 对象进行比较：

It's easier than you think. You can do comparisons with DateTime objects:

$opening_date = new DateTime($current_store['openingdate']);
$current_date = new DateTime();

if ($opening_date > $current_date)
{
  // not open yet!
}

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