如何以毫秒的粒度创建Python时间戳？ [英] How can I create a Python timestamp with millisecond granularity?

问题描述

从历元起，我需要一个毫秒（ms）的单个时间戳。这不应该是困难的，我相信我只是错过了一些 datetime 或类似的方法。

I need a single timestamp of milliseconds (ms) since epoch. This should not be hard, I am sure I am just missing some method of datetime or something similar.

实际上微秒（μs）粒度也很好。我只需要第1/10秒的时间。

Actually microsecond (µs) granularity is fine too. I just need sub 1/10th second timing.

示例。我有一个每750毫秒发生的事件，让我们来看看它是否打开或关闭。我需要记录每个检查和结果并稍后进行审查，因此我的日志需要如下所示：

Example. I have an event that happens every 750 ms, lets say it checks to see if a light is on or off. I need to record each check and result and review it later so my log needs to look like this:

...00250 Light is on
...01000 Light is off
...01750 Light is on
...02500 Light is on

如果我只有完整的第二粒度，我的日志将如下所示：

If I only have full second granularity my log would look like this:

...00 Light is on
...01 Light is off
...01 Light is on
...02 Light is on

不够准确。

推荐答案

import time
time.time() * 1000

其中1000是每秒毫秒。如果你想要的是从时代开始的百分之一秒，乘以100。

where 1000 is milliseconds per second. If all you want is hundredths of a second since the epoch, multiply by 100.

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