计算java中两个给定时间的差异b / w [英] Calculate the difference b/w two given times in java

问题描述

我正在尝试计算给定两次的差异，我发现一些问题。
假设我们有时间值是11：AM和10:00 AM
我可以计算，但AM，PM有一点混乱
提前感谢

I am trying to calculate the difference between given two times and i find some problem in it. Suppose we have times value are "11:AM" and 10:00 AM". I am able to calculate but there is a bit of confusion in AM ,PM. Thanks in advance

我正在使用以下代码：

import java.text.ParseException;
import java.text.SimpleDateFormat;
import java.util.Date;

public class StringToDate {

public static String timeDiff(String time1, String time2) {
    String Time = null;
    int difference;
    String a1 = time1.substring(6);
    String a2 = time2.substring(6);

    try {
        // Define a date format the same as the expected input
        SimpleDateFormat sdf = new SimpleDateFormat("HH:mm a");
        // Get time values of the date objects
        long l1 = sdf.parse(time1).getTime();
        long l2 = sdf.parse(time2).getTime();
        difference = (int) (l2 - l1);
        difference = (difference < 0 ? -difference : difference) / 60000;
        if (difference > 60) {
            int Hour = difference / 60;
            int Mins = difference % 60;
            if (Mins == 0)
                Time = Hour + " Hours";
            else
                Time = Hour + " Hours" + " " + Mins + " Mins";
        } else {
            Time = difference + " " + "Mins";
        }
    } catch (ParseException e) {
        e.printStackTrace();
    }
    return Time;
}

public static void main(String[] args) {
    String diff = StringToDate.timeDiff("10:00 AM", "01:00 PM");
    System.out.println("Difference: " + diff);
}

}

推荐答案

您可以获取开始和开始的日期对象时间结束。
然后得到时间在millis&

You can get date objects for both start & end time. Then get time in millis & subtract.

Millis的差异= endDate.getTime（） - startDate.getTime（）

Difference in Millis = endDate.getTime() - startDate.getTime()

转换差异到小时/分钟。

Convert the difference to hours/minutes.

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