T-SQL DateDiff - “满小时前”的分区,而不是“时间分钟变为00”,因为“ [英] T-SQL DateDiff - partition by "full hours ago", rather than "times minutes turned 00 since"
问题描述
在T-SQL中是否有直接的方法?
更新:
为了回应评论,这里有一些样本数据,我目前正在使用的查询结果,以及我想要的结果。
样本数据:
TimeStamp
*********
2010-07 -20 11:00:00.000
2010-07-20 10:44:00.000
2010-07-20 10:14:00.000
2010-07-20 11:00:00.000
2010-07-20 11:40:00.000
2010-07-20 10:16:00.000
2010-07-20 13:00:00.000
2010-07-20 12:58:00.000
当前查询:
SELECT TimeStamp,DATEDIFF(HOUR,TimeStamp,CURRENT_TIMESTAMP)AS Diff FROM ...
结果:
TimeStamp Diff
********* ****
2010-07-20 11:00:00.000 2
2010-07-20 10:44:00.000 3
2010-07-20 10:14:00.000 3
2010- 07-20 11:00:00.000 2
2010-07-20 11:40:00.000 2
2010-07-20 10:16:00.000 3
2010-07-20 13: 00:00.000 0
2010-07-20 12:58:00.000 1
我宁愿拥有:
- 现在是为了这个例子,13:40
TimeStamp Diff
******* ** ****
2010-07-20 11:00:00.000 3 - +1
2010-07-20 10:44:00.000 3
2010-07-20 10 :14:00.000 4 - +1
2010-07-20 11:00:00.000 3 - +1
2010-07-20 11:40:00.000 2或3 - ID不关心哪个
2010-07-20 10:16:00.000 4 - +1
2010-07-20 13:00:00.000 1 - +1
2010- 07-20 12:58:00.000 1
我已经标记了使用 +1更改的结果
。另外,我真的不在乎,如果这是0索引或1索引,但基本上,如果现在是13:40我希望得到相同值的时间跨度是
12:40-13:40 1(或0)
11:40-12:40 2(或1)
10:40-11:40 3 2)
09:40-10:40 4(或3)
使用 DATEDIFF(分钟,..
,然后将结果除以60并取整数值。例如
SELECT DATEDIFF(分钟,'2010-07-20 06:00',GETDATE())/ 60
我相信这将被隐式转换为一个int,因为datediff返回一个int,它给了整整一个小时,没有四舍五入。
要使用您更新的帖子中的确切查询:
SELECT TimeStamp(DATEDIFF(minute,TimeStamp,CURRENT_TIMESTAMP)/ 60)AS Diff FROM ...
I have a table with timestamps, and I want to partition this table into hour-long intervals, starting at now and going backwards a couple of hours. I'm unable to get the results I need with the T-SQL DATEDIFF function, since it counts the number of times the minute hand passes 12 between the two dates - I want the number of times them minute hand passes where it is now between the timestamp and now.
Is there a straightforward way to do this in T-SQL?
Update: In response to comments, here's some sample data, the query I'm currently using and the results I'm getting, as well as the results I want.
Sample data:
TimeStamp
*********
2010-07-20 11:00:00.000
2010-07-20 10:44:00.000
2010-07-20 10:14:00.000
2010-07-20 11:00:00.000
2010-07-20 11:40:00.000
2010-07-20 10:16:00.000
2010-07-20 13:00:00.000
2010-07-20 12:58:00.000
Current query:
SELECT TimeStamp, DATEDIFF(HOUR, TimeStamp, CURRENT_TIMESTAMP) AS Diff FROM ...
Results:
TimeStamp Diff ********* **** 2010-07-20 11:00:00.000 2 2010-07-20 10:44:00.000 3 2010-07-20 10:14:00.000 3 2010-07-20 11:00:00.000 2 2010-07-20 11:40:00.000 2 2010-07-20 10:16:00.000 3 2010-07-20 13:00:00.000 0 2010-07-20 12:58:00.000 1
What I'd rather have:
-- The time is now, for the sake of the example, 13:40 TimeStamp Diff ********* **** 2010-07-20 11:00:00.000 3 -- +1 2010-07-20 10:44:00.000 3 2010-07-20 10:14:00.000 4 -- +1 2010-07-20 11:00:00.000 3 -- +1 2010-07-20 11:40:00.000 2 or 3 -- edge case, I don't really care which 2010-07-20 10:16:00.000 4 -- +1 2010-07-20 13:00:00.000 1 -- +1 2010-07-20 12:58:00.000 1
I've marked the results that changed with a +1
. Also, I don't really care if this is 0-indexed or 1-indexed, but basically, if it's now 13:40 I want the time spans that get the same value to be
12:40-13:40 1 (or 0) 11:40-12:40 2 (or 1) 10:40-11:40 3 (or 2) 09:40-10:40 4 (or 3)
Can you not just use DATEDIFF(minute,..
and then divide the result by 60 and take the integer value. e.g.
SELECT DATEDIFF(minute, '2010-07-20 06:00', GETDATE())/60
I believe this will be implicitly cast as an int as datediff returns an int, it gives whole hours with no rounding.
To use your exact query from your updated post:
SELECT TimeStamp, (DATEDIFF(minute, TimeStamp, CURRENT_TIMESTAMP) /60) AS Diff FROM ...
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