从Python中复杂的字符串检索日期 [英] Retrieving a date from a complex string in Python

问题描述

我正在尝试使用datetime.strptime从两个字符串中获取单个datetime。

I'm trying to get a single datetime out of two strings using datetime.strptime.

时间很简单（例如下午8:53），所以我可以做一些像：

The time is pretty easy (ex. 8:53PM), so I can do something like:

theTime = datetime.strptime(givenTime, "%I:%M%p")

但是，字符串不仅仅是一个日期，它是一个类似于 http://site.com/?year=2011&month=10&day=的格式的链接5& hour = 11 。我知道我可以这样做：

However, the string has more than just a date, it's a link in a format similar to http://site.com/?year=2011&month=10&day=5&hour=11. I know that I could do something like:

theDate = datetime.strptime(givenURL, "http://site.com/?year=%Y&month=%m&day=%d&hour=%H")

但是我不希望从链接中获取那个小时，因为它被其他地方检索。有没有办法把一个虚拟符号（比如％x或某些东西）作为最后一个变量的灵活空间？

but I don't want to get that hour from the link since it's being retrieved elsewhere. Is there a way to put a dummy symbol (like %x or something) to serve as a flexible space for that last variable?

最后，我设想有一个单行类似于：

In the end, I envision having a single line similar to:

theDateTime = datetime.strptime(givenURL + givenTime, ""http://site.com/?year=%Y&month=%m&day=%d&hour=%x%I:%M%p")

（虽然显然，％x不会被使用）任何想法？

(although, obviously, the %x wouldn't be used). Any ideas?

推荐答案

想想，如果你想从URL简单的跳过时间，你可以使用split例如以下方式：

Think that if you would like to simple skip time from the URL you can use split for example the following way:

givenURL = 'http://site.com/?year=2011&month=10&day=5&hour=11'
pattern = "http://site.com/?year=%Y&month=%m&day=%d"
theDate = datetime.strptime(givenURL.split('&hour=')[0], pattern)

所以不知道你是否正确理解，但是：

So not sure that understood you correctly, but:

givenURL = 'http://site.com/?year=2011&month=10&day=5&hour=11'
datePattern = "http://site.com/?year=%Y&month=%m&day=%d"
timePattern = "&time=%I:%M%p"

theDateTime = datetime.strptime(givenURL.split('&hour=')[0] + '&time=' givenTime, datePattern + timePattern)

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