获取PHP之前的最后一个星期四 [英] get the last thursday before a date in PHP

问题描述

我知道有关于如何在PHP中获得最后一个星期四的相似文章，但是我不想让最后一个星期四与当前日期相比较，但上周四比较给定日期。

I know there is similar post about how to get the last Thursday in PHP but I don't want to have the last Thursday compare to the current date but the last Thursday compare to a given date.

例如我有一个日期dd / mm / yyyy，我想在这个日期之前的星期四。
输入是一个字符串（字符串yymmdd的格式），我想解析以获取此日期之前的星期四。

For example I have a date dd/mm/yyyy and I want the Thursday before this date. The input is a String ( the format of the string yymmdd) that I want to parse to get the Thursday before this date.

感谢您的帮助

推荐答案

//Assumes it's strtotime parsable, you may need to insert
//  slashes with your given format eg (and use 4 digit years)
$given=strtotime($dtstring);

//It's just that easy ;)
$thuBefore=strtotime("last thursday",$given);

请注意，这将永远获得上一个星期四，这意味着如果给定的日期是星期四，它会在7天前报告（但如果日期是星期五，那只会在前一天提前报告）。

Note that this will always get last thursday, meaning if the given date is a Thursday, it'll report 7 days earlier (but if the date's a Friday it'll only report one day earlier).

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