日期差异仅考虑年月日 [英] Date difference only considering year month day

问题描述

我想计算日期差异，只考虑年，月，日在php。现在程序计算日期差异考虑到所有的日期时间对象参数。

I want to calculate date difference only considering year,month and day in php. Now the program calculate date difference considering all of the date time object parameter.

$DTObj = new DateTime();
$pdate = DateTime::createFromFormat("ymd", 141118);
$diff = $DTObj->diff($pdate);
$dday = $diff->format("%a");

我如何实现这一点？

推荐答案

阅读并尝试：

# create DateTime object with time at 00:00:00
$from = new DateTime('today'); 

# create DateTime object from ymd format
# format character ! resets all fields (year, month, ...) to the Unix Epoch and then sets the inputed date
$to = DateTime::createFromFormat('!ymd', '141118');

# calculate difference between $from and $to and return DateInterval object
$diff = $from->diff($to);

# echo difference of total number of days
echo $diff->format('%a');

演示

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