如何在字符串中找到子字符串（或如何grep变量）？ [英] How to find substring inside a string (or how to grep a variable)?

问题描述

我使用的是BASH，我不知道如何找到一个子字符串。

I'm using BASH, and I don't know how to find a substring. It keeps failing, I've got a string (should this be an array?)

下面， LIST 是一个字符串（应该是一个数组）数据库名称的字符串列表 SOURCE 是回复，其中一个数据库。以下仍然无效：

Below, LIST is a string list of database names, SOURCE is the reply, one of those databases. The following still doesn't work:

echo "******************************************************************"
echo "*                  DB2 Offline Backup Script                     *"
echo "******************************************************************"
echo "What's the name of of the  database you would like to backup?"
echo "It will be named one in this list:"
echo ""
LIST=`db2 list database directory | grep "Database alias" | awk '{print $4}'`
echo $LIST
echo ""
echo "******************************************************************"
echo -n ">>> "
read -e SOURCE

if expr match "$LIST" "$SOURCE"; then
    echo "match"
    exit -1
else
    echo "no match"
fi
exit -1

我也尝试过但不起作用：

I've also tried this but doesn't work:

if [ `expr match "$LIST" '$SOURCE'` ]; then

推荐答案

LIST="some string with a substring you want to match"
SOURCE="substring"
if echo "$LIST" | grep -q "$SOURCE"; then
  echo "matched";
else
  echo "no match";
fi

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