检测连续整数以列表 [英] Detecting consecutive integers in a list

问题描述

我有一个包含数据，这样一份清单：

I have a list containing data as such:

[1, 2, 3, 4, 7, 8, 10, 11, 12, 13, 14]

我想打印出连续的整数范围：

I'd like to print out the ranges of consecutive integers:

1-4, 7-8, 10-14

有一个内置/快速/高效这样的方式？

Is there a built-in/fast/efficient way of doing this?

推荐答案

从的文档< /一>：

From the docs:

>>> from itertools import groupby
>>> from operator import itemgetter
>>> data = [ 1, 4,5,6, 10, 15,16,17,18, 22, 25,26,27,28]
>>> for k, g in groupby(enumerate(data), lambda (i, x): i-x):
...     print map(itemgetter(1), g)
...
[1]
[4, 5, 6]
[10]
[15, 16, 17, 18]
[22]
[25, 26, 27, 28]

您可以适应这个很容易得到一个印刷的范围集合。

You can adapt this fairly easily to get a printed set of ranges.

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