凡在JavaScript中我单行执行ROT13的问题呢？ [英] Where is my one-line implementation of rot13 in JavaScript going wrong?

问题描述

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Code in question with syntax highlighting here: via Friendpaste

rot13.js：

<script>
String.prototype.rot13 = rot13 = function(s)
 {
    return (s = (s) ? s : this).split('').map(function(_)
     {
    	if (!_.match(/[A-Za-z]/)) return _;
    	c = Math.floor(_.charCodeAt(0) / 97);
    	k = (_.toLowerCase().charCodeAt(0) - 96) % 26 + 13;
    	return String.fromCharCode(k + ((c == 0) ? 64 : 96));
     }).join('');
 };
</script>

正如你所看到的，使用毫不夸张一行附加一个方法，String对象一拉成型，我有一张地图（）方法，我previously成立了（我知道肯定是code完美的作品，它只是遍历数组中的每个元素和应用参数中指定的函数）去了每一个字符的字符串，做我认为是正确的计算转换串入它的rot13'd对口。我是大错特错了。任何人都可以发现我哪里错了？

As you can see, using quite literally a single line to attach a method to the String object a la prototyping, I'm having a map() method that I previously set up (I know for sure that that code works perfectly; it's simply iterating over each element in the array and applying the function specified in the parameter) go over each character in a string and do what I thought were the proper calculations to transform the string into it's rot13'd counterpart. I was sadly mistaken. Can anybody spot where I went wrong?

推荐答案

您可以使用超级短：

s.replace(/[a-zA-Z]/g,function(c){return String.fromCharCode((c<="Z"?90:122)>=(c=c.charCodeAt(0)+13)?c:c-26);});

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