使用Unity填充收集的方式 [英] Way to fill collection with Unity
问题描述
我有两个示例类
class ClassToResolve
{
private List<CollectionItem> _coll;
public ClassToResolve(List<CollectionItem> coll)
{
_coll = coll;
}
}
class CollectionItem
{
//...
}
,我需要解决ClassToResolve
and I need to resolve ClassToResolve
var classToResolve = new ClassToResolve(
new List<CollectionItem>()
{
new CollectionItem(),
new CollectionItem(),
new CollectionItem()
}
);
现在我以某种方式解决了
Now I resolve it in a way
var classToResolve = new ClassToResolve(
new List<CollectionItem>()
{
unity.Resolve<CollectionItem>(),
unity.Resolve<CollectionItem>(),
unity.Resolve<CollectionItem>()
}
);
有没有办法使用动态注册来解决使用Unity的ClassToResolve?
Is there a way to resolve ClassToResolve with Unity using dynamic registration?
推荐答案
Unity将明白 T []
(array)事物列表(但不是 IEnumerable< T>
,而不是列表< T>
)。当您将 ClassToResolve
的构造函数更改为采用 CollectionItem []
而不是列表< CollectionItem>
可以如下配置 CollectionItem
类型:
Unity will understand that T[]
(array) dependencies are a list of things (but not IEnumerable<T>
, nor List<T>
). When you change the constructor of ClassToResolve
to take an CollectionItem[]
instead of a List<CollectionItem>
you can configure your CollectionItem
types as follows:
container.RegisterType<CollectionItem, CollectionItemA>("a");
container.RegisterType<CollectionItem, CollectionItemB>("b");
container.RegisterType<CollectionItem, CollectionItemC>("c");
container.RegisterType<CollectionItem, CollectionItemD>("d");
这里的诀窍是命名所有注册。默认(无名)注册将永远不会是Unity中序列依赖关系的一部分。
The trick here is to name all the registrations. A default (nameless) registration will never be part of a sequence dependency in Unity.
现在您可以解析 ClassToResolve
而不需要注册:
Now you can resolve ClassToResolve
without the need to register it:
container.Resolve<ClassToResolve>();
如果你注意列表< CollectionItem>
您可以添加以下注册:
If you rather inject List<CollectionItem>
you can add the following registration:
container.RegisterType<IList<CollectionItem>, CollectionItem[]>();
而对于 IEnumerable< CollectionItem>
添加以下行:
container
.RegisterType<IEnumerable<CollectionItem>, CollectionItem[]>();
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