模糊日期算法在Objective-C [英] Fuzzy Date algorithm in Objective-C
问题描述
我想编写一个模糊的日期计算方法日期在Objective-C的iPhone。有一种流行的解释一下:
<一个href="http://stackoverflow.com/questions/11/how-do-i-calculate-relative-time">http://stackoverflow.com/questions/11/how-do-i-calculate-relative-time
然而,它包含缺少的参数。怎样才能在Objective-C本中使用?谢谢你。
const int的第二= 1;
const int的分钟= 60 *秒;
const int的小时= 60 *分;
const int的天= 24 *小时,
const int的月= 30 *天;
如果(增量&LT; 1 *分钟)
{
返回ts.Seconds == 1? 一秒钟前:ts.Seconds +秒前;
}
如果(△2 *分钟)的
{
返回一分钟前;
}
如果(增量&LT; 45 *分)
{
返回ts.Minutes +分钟前;
}
如果(增量&LT; 90 *分)
{
返回一个小时前;
}
如果(增量&LT; 24 * HOUR)
{
返回ts.Hours +小时前;
}
如果(增量&LT; 48 * HOUR)
{
回归昨天;
}
如果(增量小于30 *天)
{
返回ts.Days +日前;
}
如果(增量&LT; 12 *月)
{
INT个月= Convert.ToInt32(Math.Floor((双)ts.Days / 30));
返回月&其中; = 1? 一个月前:个月+几个月前;
}
其他
{
INT年= Convert.ToInt32(Math.Floor((双)ts.Days / 365));
返回年&其中; = 1? 一年前:年+年前;
}
日期重新$ P $使用的NSDate
类psented可可。有一个在的NSDate
实施了方便的方法来获取增量在几秒钟内两个日期实例之间,<一个href="http://developer.apple.com/DOCUMENTATION/Cocoa/Reference/Foundation/Classes/NSDate%5FClass/Reference/Reference.html#//apple%5Fref/occ/instm/NSDate/timeIntervalSinceDate:"><$c$c>timeIntervalSinceDate:$c$c>.这就是所谓的在一个的NSDate
实例,同时另一个的NSDate
对象作为参数。它返回一个<一个href="http://developer.apple.com/DOCUMENTATION/Cocoa/Reference/Foundation/Miscellaneous/Foundation%5FDataTypes/Reference/reference.html#//apple%5Fref/doc/c%5Fref/NSTimeInterval"><$c$c>NSTimeInterval$c$c> (这是一个typedef用于双),这是秒的两个日期之间的数目的重presentative
鉴于此,这将是相当简单的,以适应code,你在上面给一个Objective-C /可可上下文。由于通过的NSDate
计算的增量以秒为单位,考虑到两个日期,你可以很容易地适应code以上:
//常量
#定义每秒1
#定义分钟(60 *第二)
#定义小时(60 *分钟)
#定义天(24 * HOUR)
#定义MONTH(30 *天)
- (的NSString *)timeIntervalWithStartDate:(的NSDate *)D1 withEndDate:(的NSDate *)D2
{
//计算增量以秒为单位的两个日期之间
NSTimeInterval增量= [D2 timeIntervalSinceDate:D1];
如果(增量&LT; 1 *分钟)
{
返回三角洲== 1? @一秒钟前:[的NSString stringWithFormat:@%d秒前,(INT)三角洲]。
}
如果(△2 *分钟)的
{
返回@一分钟前;
}
如果(增量&LT; 45 *分)
{
INT分钟=地板((双)增量/分钟);
返回[的NSString stringWithFormat:@%d分钟前,分]
}
如果(增量&LT; 90 *分)
{
返回@一个小时前;
}
如果(增量&LT; 24 * HOUR)
{
INT小时=地板((双)增量/小时);
返回[的NSString stringWithFormat:@%d小时前,时间]。
}
如果(增量&LT; 48 * HOUR)
{
返回@昨天;
}
如果(增量小于30 *天)
{
INT天=地板((双)三角洲/天);
返回[的NSString stringWithFormat:@%d天前天]。
}
如果(增量&LT; 12 *月)
{
INT个月=地板((双)增量/月);
返回月&其中; = 1? @一个月前:[的NSString stringWithFormat:@%d个月前,月];
}
其他
{
INT年=地板((双)三角洲/月/ 12.0);
返回年&其中; = 1? @一年前:[的NSString stringWithFormat:@%D年前,年]。
}
}
这将被调用,传递的开始和结束的NSDate
对象作为参数,并会返回一个的NSString
同的时间间隔。
I would like to write a fuzzy date method for calculating dates in Objective-C for iPhone. There is a popular explanation here:
http://stackoverflow.com/questions/11/how-do-i-calculate-relative-time
However it contains missing arguments. How could this be used in Objective-C?. Thanks.
const int SECOND = 1;
const int MINUTE = 60 * SECOND;
const int HOUR = 60 * MINUTE;
const int DAY = 24 * HOUR;
const int MONTH = 30 * DAY;
if (delta < 1 * MINUTE)
{
return ts.Seconds == 1 ? "one second ago" : ts.Seconds + " seconds ago";
}
if (delta < 2 * MINUTE)
{
return "a minute ago";
}
if (delta < 45 * MINUTE)
{
return ts.Minutes + " minutes ago";
}
if (delta < 90 * MINUTE)
{
return "an hour ago";
}
if (delta < 24 * HOUR)
{
return ts.Hours + " hours ago";
}
if (delta < 48 * HOUR)
{
return "yesterday";
}
if (delta < 30 * DAY)
{
return ts.Days + " days ago";
}
if (delta < 12 * MONTH)
{
int months = Convert.ToInt32(Math.Floor((double)ts.Days / 30));
return months <= 1 ? "one month ago" : months + " months ago";
}
else
{
int years = Convert.ToInt32(Math.Floor((double)ts.Days / 365));
return years <= 1 ? "one year ago" : years + " years ago";
}
Dates are represented in Cocoa using the NSDate
class. There is a convenient method implemented in NSDate
to obtain the delta in seconds between two date instances, timeIntervalSinceDate:
. This is called upon an NSDate
instance, taking another NSDate
object as an argument. It returns an NSTimeInterval
(which is a typedef for a double), which is representative of the number of seconds between the two dates.
Given this, it would be fairly simple to adapt the code you have given above to an Objective-C/Cocoa context. Since the delta calculated by NSDate
is given in seconds, given two dates, you could easily adapt the code above:
//Constants
#define SECOND 1
#define MINUTE (60 * SECOND)
#define HOUR (60 * MINUTE)
#define DAY (24 * HOUR)
#define MONTH (30 * DAY)
- (NSString*)timeIntervalWithStartDate:(NSDate*)d1 withEndDate:(NSDate*)d2
{
//Calculate the delta in seconds between the two dates
NSTimeInterval delta = [d2 timeIntervalSinceDate:d1];
if (delta < 1 * MINUTE)
{
return delta == 1 ? @"one second ago" : [NSString stringWithFormat:@"%d seconds ago", (int)delta];
}
if (delta < 2 * MINUTE)
{
return @"a minute ago";
}
if (delta < 45 * MINUTE)
{
int minutes = floor((double)delta/MINUTE);
return [NSString stringWithFormat:@"%d minutes ago", minutes];
}
if (delta < 90 * MINUTE)
{
return @"an hour ago";
}
if (delta < 24 * HOUR)
{
int hours = floor((double)delta/HOUR);
return [NSString stringWithFormat:@"%d hours ago", hours];
}
if (delta < 48 * HOUR)
{
return @"yesterday";
}
if (delta < 30 * DAY)
{
int days = floor((double)delta/DAY);
return [NSString stringWithFormat:@"%d days ago", days];
}
if (delta < 12 * MONTH)
{
int months = floor((double)delta/MONTH);
return months <= 1 ? @"one month ago" : [NSString stringWithFormat:@"%d months ago", months];
}
else
{
int years = floor((double)delta/MONTH/12.0);
return years <= 1 ? @"one year ago" : [NSString stringWithFormat:@"%d years ago", years];
}
}
This would then be called, passing the start and end NSDate
objects as arguments, and would return an NSString
with the time interval.
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