Android对话框,当按下按钮时,保持对话框打开 [英] Android Dialog, keep dialog open when button is pressed
问题描述
当我按下按钮时,我想保持对话框打开。
当前正在关闭。
I would like to keep my dialog open when I press a button. At the moment it's closing.
AlertDialog.Builder builder = new AlertDialog.Builder(this);
builder.setMessage("Are you sure you want to exit?")
.setCancelable(false)
.setPositiveButton("Yes", new DialogInterface.OnClickListener() {
public void onClick(DialogInterface dialog, int id) {
MyActivity.this.finish();
}
})
.setNegativeButton("No", new DialogInterface.OnClickListener() {
public void onClick(DialogInterface dialog, int id) {
dialog.cancel();
}
});
AlertDialog alert = builder.create();
推荐答案
是的,你可以。您基本上需要:
Yes, you can. You basically need to:
- 使用 DialogBuilder 创建对话框
- show()对话框
- 找到所显示对话框中的按钮,并覆盖他们的
onClickListener
- Create the dialog with DialogBuilder
- show() the dialog
- Find the buttons in the dialog shown and override their
onClickListener
所以,创建一个监听器类:
So, create a listener class:
class CustomListener implements View.OnClickListener {
private final Dialog dialog;
public CustomListener(Dialog dialog) {
this.dialog = dialog;
}
@Override
public void onClick(View v) {
// Do whatever you want here
// If you want to close the dialog, uncomment the line below
//dialog.dismiss();
}
}
然后在显示对话框时使用:
Then when showing the dialog use:
AlertDialog dialog = dialogBuilder.create();
dialog.show();
Button theButton = dialog.getButton(DialogInterface.BUTTON_POSITIVE);
theButton.setOnClickListener(new CustomListener(dialog));
请记住,您需要显示对话框,否则按钮将无法找到。另外,请确保将 DialogInterface.BUTTON_POSITIVE 更改为用于添加按钮的任何值。另请注意,在 DialogBuilder 中添加按钮时,您需要提供 onClickListeners
- 您不能在其中添加自定义侦听器 - 调用 show()
后,如果不覆盖监听器,对话框仍然会被关闭。
Remember, you need to show the dialog otherwise the button will not be findable. Also, be sure to change DialogInterface.BUTTON_POSITIVE to whatever value you used to add the button. Also note that when adding the buttons in the DialogBuilder you will need to provide onClickListeners
- you can not add the custom listener in there, though - the dialog will still dismiss if you do not override the listeners after show()
is called.
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