如何将所选文件从对话窗口添加到字典? [英] how to add the selected files from dialog window to a dictionary?
问题描述
我希望能够打开一个对话窗口并选择我的文件,
a.txt
b。 txt
然后将其添加到我的字典中
myDict = {a.txt:0,
b.txt:1}
我在网站上搜索
import Tkinter,tkFileDialog
root = Tkinter.Tk()
filez = tkFileDialog.askopenfilenames(parent = root,multiple ='multiple',title ='选择一个文件')
这些代码用于打开对话窗口并选择我的文件。
但问题是如何将所选文件添加到字典?
与Stephan的答案一起,问题解决了
$ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $$ en + str(myDict)
现在myDict是
myDict = {'C:/a.txt':0}
myDict = {'C:/a.txt':0,'C:/ b。 txt':1}
在网上搜索后,只需添加os.path.split
myDict = {}
在filez中的文件名:
head,tail = os.path.split(str(filename) )
myDict [tail] = len(myDict)
现在一切正确
myDict = {'a.txt':0,'b.txt':1}
我的myDict没有路径,问题解决了!
谢谢!
myDict = {}
myDict [ filenameFromDialog] = len(myDict)
这是添加到字典的语法。
如果您有要添加到字典的文件数组,您可以循环遍历列表,并一次添加一个:
myDict = {}
在filez中的文件名:
myDict [filename] = len(myDict)
I wish it's able to open a dialog window and select my files,
a.txt
b.txt
then add them in my dictionary
myDict = { "a.txt" : 0,
"b.txt" : 1}
I searched on website
import Tkinter,tkFileDialog
root = Tkinter.Tk()
filez = tkFileDialog.askopenfilenames(parent=root,multiple='multiple',title='Choose a file')
these codes work for opening a dialog window and selecting my files. But the question is how to add the selected files to the dictionary?
With Stephan's answer, the problem is solved
myDict = {}
for filename in filez:
myDict[filename] = len(myDict)
print "myDict: " + str(myDict)
Now the myDict is
myDict = {'C:/a.txt': 0}
myDict = {'C:/a.txt': 0, 'C:/b.txt': 1}
After searching online, just add os.path.split
myDict = {}
for filename in filez:
head, tail = os.path.split(str(filename))
myDict[tail] = len(myDict)
Now everything is right
myDict = {'a.txt': 0, 'b.txt': 1}
I got the myDict without path, problem solved! Thanks!
myDict = {}
myDict[filenameFromDialog] = len(myDict)
That is the syntax for adding to a dictionary.
If you have an array of files you want to add to the dictionary, you could loop over the list and add them one at a time:
myDict = {}
for filename in filez:
myDict[filename] = len(myDict)
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