Python文件对话框问题 [英] Python file dialog issue

问题描述

我正在尝试使用Tkinter选择一个文件，然后将该文件名导入参数以传入一个函数。程序在选择文件后才会停止。我包含一个print语句，只是为了看看它是否返回路径，这样做，我不知道为什么它不会在函数中工作。

I am trying to use Tkinter to choose a file and then import that filename into an argument to pass in a function. The program simply stops after the file is chosen. I included a print statement just to see if it returns the path and it does so I am not sure why it won't work in the function.

#Main

from Tkinter import *
import tkFileDialog


fileOpen = Tk()
fileOpen.withdraw() #hiding tkinter window

file_path = tkFileDialog.askopenfilename(title="Open file", filetypes=[("txt file",".txt"),("All files",".*")])

if file_path != "":
   print "you chose file with path:", file_path

else:
   print "you didn't open anything!"

master.quit()

print file_path   


spaceParser (file_path,'r','/Users/Desktop/TygerTygerParsed.txt','w')

推荐答案

版本）工作正常：

from Tkinter import *
import tkFileDialog

fileOpen = Tk()
fileOpen.withdraw() #hiding tkinter window

file_path = tkFileDialog.askopenfilename(
    title="Open file", filetypes=[("txt file",".txt"),("All files",".*")])

if file_path != "":
   print "you chose file with path:", file_path

else:
   print "you didn't open anything!"

print file_path   

所以我猜你的程序暂停在

So I'm guessing your program is halting on

master.quit()

这篇关于Python文件对话框问题的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！