类java.util.Map具有通用类型参数,请改用GenericTypeIndicator [英] Class java.util.Map has generic type parameters, please use GenericTypeIndicator instead

查看:470
本文介绍了类java.util.Map具有通用类型参数,请改用GenericTypeIndicator的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我正在使用firebase从数据库中检索数据n使用

I am using firebase to retrieve data from database n use

Map< String,String> map = dataSnapshot.getValue(Map.class);

获取值,但显示错误

E/AndroidRuntime: FATAL EXCEPTION: main
                                                                 Process: com.rana.sahaj.myyu, PID: 13179
                                                                 com.google.firebase.database.DatabaseException: Class java.util.Map has generic type parameters, please use GenericTypeIndicator instead
                                                                     at com.google.android.gms.internal.zzaix.zzb(Unknown Source)
                                                                     at com.google.android.gms.internal.zzaix.zza(Unknown Source)
                                                                     at com.google.firebase.database.DataSnapshot.getValue(Unknown Source)
                                                                     at com.rana.sahaj.myyu.profile.Profile$2.onDataChange(Profile.java:158)
                                                                     at com.google.android.gms.internal.zzafp.zza(Unknown Source)
                                                                     at com.google.android.gms.internal.zzagp.zzSu(Unknown Source)
                                                                     at com.google.android.gms.internal.zzags$1.run(Unknown Source)
                                                                     at android.os.Handler.handleCallback(Handler.java:733)
                                                                     at android.os.Handler.dispatchMessage(Handler.java:95)
                                                                     at android.os.Looper.loop(Looper.java:136)
                                                                     at android.app.ActivityThread.main(ActivityThread.java:5052)
                                                                     at java.lang.reflect.Method.invokeNative(Native Method)
                                                                     at java.lang.reflect.Method.invoke(Method.java:515)
                                                                     at com.android.internal.os.ZygoteInit$MethodAndArgsCaller.run(ZygoteInit.java:793)
                                                                     at com.android.internal.os.ZygoteInit.main(ZygoteInit.java:609)
                                                                     at dalvik.system.NativeStart.main(Native Method)

这里是代码

 DatabaseReference profileRef=mFirebaseRef.child(EEmail);
    profileRef.addValueEventListener(new ValueEventListener() {
        @Override
        public void onDataChange(DataSnapshot dataSnapshot) {

    -->     Map<String, String> map = (Map<String,String>)dataSnapshot.getValue(Map.class);

            name = (TextView)findViewById(R.id.UserInActivity);
            EmailView= (TextView)findViewById(R.id.emailUser);

            PhotoUrl = map.get("picurl");
             emmaill=map.get("userEmail");

            UserNam = map.get("userNAME");

            name.setText(UserNam);
            EmailView.setText(emmaill);


        }

        @Override
        public void onCancelled(DatabaseError firebaseError) {

        }
    });

n数据库中的键n值没有问题。
使用解决方案,但不能工作

n there is no problem with key n values in database. used the solution but not working

推荐答案

错误正确地指出您错误的地方

The error points out correctly where you are going wrong

 Map<String, String> map = dataSnapshot.getValue(Map.class);

Map类使用参数定义Key和Object 的类型,其中as你不给他们,只需使用 Map.class ,这个失败。

Map class uses parameter to define the types of Key and Object where as you don't give them and simply use Map.class which fails.

尝试下面的代码 - 从Key总是字符串,我们可以为他们提供任何类型的对象

Try the below code - since Key are always string and we can have any type of Object for them

    Map<String, Object> map = (Map<String, Object>) dataSnapshot.getValue();

这篇关于类java.util.Map具有通用类型参数,请改用GenericTypeIndicator的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

查看全文
登录 关闭
扫码关注1秒登录
发送“验证码”获取 | 15天全站免登陆