按多个键进行分组，并汇总/列出词典的平均值 [英] Group by multiple keys and summarize/average values of a list of dictionaries

问题描述

通过多个按键组合最多的pythonic方式是什么，并在Python中总结/列出词典的平均值？说我有一个字典列表如下：

What is the most pythonic way to group by multiple keys and summarize/average values of a list of dictionaries in Python please? Say I have a list of dictionaries as below:

input = [
{'dept': '001', 'sku': 'foo', 'transId': 'uniqueId1', 'qty': 100},
{'dept': '001', 'sku': 'bar', 'transId': 'uniqueId2', 'qty': 200},
{'dept': '001', 'sku': 'foo', 'transId': 'uniqueId3', 'qty': 300},
{'dept': '002', 'sku': 'baz', 'transId': 'uniqueId4', 'qty': 400},
{'dept': '002', 'sku': 'baz', 'transId': 'uniqueId5', 'qty': 500},
{'dept': '002', 'sku': 'qux', 'transId': 'uniqueId6', 'qty': 600},
{'dept': '003', 'sku': 'foo', 'transId': 'uniqueId7', 'qty': 700}
]

期望的汇总输出：

output=[
{'dept': '001', 'sku': 'foo', 'qty': 400},
{'dept': '001', 'sku': 'bar', 'qty': 200},
{'dept': '002', 'sku': 'baz', 'qty': 900},
{'dept': '002', 'sku': 'qux', 'qty': 600},
{'dept': '003', 'sku': 'foo', 'qty': 700}
]

或平均值：

output=[
{'dept': '001', 'sku': 'foo', 'avg': 200},
{'dept': '001', 'sku': 'bar', 'avg': 200},
{'dept': '002', 'sku': 'baz', 'avg': 450},
{'dept': '002', 'sku': 'qux', 'avg': 600},
{'dept': '003', 'sku': 'foo', 'avg': 700}
]

我发现这个：通过并聚合Python中词典列表的值，但它不'似乎给我我想要的。

I have found this: Group by and aggregate the values of a list of dictionaries in Python but it doesn't seem to give me what I want.

推荐答案

从运算符import itemgetter $ b获取聚合结果

To get the aggregated results

from itertools import groupby
from operator import itemgetter

grouper = itemgetter("dept", "sku")
result = []
for key, grp in groupby(sorted(input_data, key = grouper), grouper):
    temp_dict = dict(zip(["dept", "sku"], key))
    temp_dict["qty"] = sum(item["qty"] for item in grp)
    result.append(temp_dict)

from pprint import pprint
pprint(result)

输出

[{'dept': '001', 'qty': 200, 'sku': 'bar'},
 {'dept': '001', 'qty': 400, 'sku': 'foo'},
 {'dept': '002', 'qty': 900, 'sku': 'baz'},
 {'dept': '002', 'qty': 600, 'sku': 'qux'},
 {'dept': '003', 'qty': 700, 'sku': 'foo'}]

为了获得平均值，您可以简单地更改内容side for for循环，像这样

And to get the averages, you can simply change the contents inside the for loop, like this

temp_dict = dict(zip(["dept", "sku"], key))
temp_list = [item["qty"] for item in grp]
temp_dict["avg"] = sum(temp_list) / len(temp_list)
result.append(temp_dict)

输出

[{'avg': 200, 'dept': '001', 'sku': 'bar'},
 {'avg': 200, 'dept': '001', 'sku': 'foo'},
 {'avg': 450, 'dept': '002', 'sku': 'baz'},
 {'avg': 600, 'dept': '002', 'sku': 'qux'},
 {'avg': 700, 'dept': '003', 'sku': 'foo'}]

建议：无论如何，我会添加 / code>和 avg 在同一个 dict 像这样

Suggestion: Anyway, I would have added both the qty and avg in the same dict like this

temp_dict = dict(zip(["dept", "sku"], key))
temp_list = [item["qty"] for item in grp]
temp_dict["qty"] = sum(temp_list)
temp_dict["avg"] = temp_dict["qty"] / len(temp_list)
result.append(temp_dict)

输出

[{'avg': 200, 'dept': '001', 'qty': 200, 'sku': 'bar'},
 {'avg': 200, 'dept': '001', 'qty': 400, 'sku': 'foo'},
 {'avg': 450, 'dept': '002', 'qty': 900, 'sku': 'baz'},
 {'avg': 600, 'dept': '002', 'qty': 600, 'sku': 'qux'},
 {'avg': 700, 'dept': '003', 'qty': 700, 'sku': 'foo'}]

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