将Python字典排列组合到词典列表中 [英] Combine Python Dictionary Permutations into List of Dictionaries

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问题描述

给出一个如下所示的字典:

  {
'颜色':['红','黄色']
'Size':['Small','Medium','Large']
}

如何创建一个组合第一个字典键的各种值的字典列表?我想要的是:

  [
{'Color':'Red','Size' },
{'Color':'Red','Size':'Medium'},
{'Color':'Red','Size':'Large'},
{'Color':'Yellow','Size':'Small'},
{'Color':'Yellow','Size':'Medium'},
{'Color'黄色','大小':'大'}
]


解决方案

我想你想要笛卡尔乘积,而不是排列,在这种情况下, itertools.product 可以帮助:

  >>>来自itertools import product 
>>>> d = {'Color':['Red','Yellow'],'Size':['Small','Medium','Large']}
>>>对于v in product(* d.values())中的[dict(zip(d,v))]
[{'Color':'Red','Size':'Small'},{'Color' :'''''''''''''''''''''''''''''''''' {'Color':'Yellow','Size':'Medium'},{'Color':'Yellow','Size':'Large'}]


Given a dictionary that looks like this:

{
    'Color': ['Red', 'Yellow'],
    'Size': ['Small', 'Medium', 'Large']
}

How can I create a list of dictionaries that combines the various values of the first dictionary's keys? What I want is:

[
    {'Color': 'Red', 'Size': 'Small'},
    {'Color': 'Red', 'Size': 'Medium'},
    {'Color': 'Red', 'Size': 'Large'},
    {'Color': 'Yellow', 'Size': 'Small'},
    {'Color': 'Yellow', 'Size': 'Medium'},
    {'Color': 'Yellow', 'Size': 'Large'}
]

解决方案

I think you want the Cartesian product, not a permutation, in which case itertools.product can help:

>>> from itertools import product
>>> d = {'Color': ['Red', 'Yellow'], 'Size': ['Small', 'Medium', 'Large']}
>>> [dict(zip(d, v)) for v in product(*d.values())]
[{'Color': 'Red', 'Size': 'Small'}, {'Color': 'Red', 'Size': 'Medium'}, {'Color': 'Red', 'Size': 'Large'}, {'Color': 'Yellow', 'Size': 'Small'}, {'Color': 'Yellow', 'Size': 'Medium'}, {'Color': 'Yellow', 'Size': 'Large'}]

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