在包含特定字符串的python字典中过滤项目 [英] filter items in a python dictionary where keys contain a specific string
问题描述
我有一个字典d,我想操作一个子集的项目,只有那些key(string)包含一个特定的子字符串。
即C逻辑将是:
用于d中的键:
如果key_string在key中:
#do
else
#不做任何操作,继续
我想象的是python版本会像
filtered_dict = crazy_python_syntax(d,substring)
用于键,filtered_dict.iteritems中的值( ):
#做某事
我在这里发现了很多关于过滤的帖子字典,但找不到一个涉及到这一点。
我的字典不是嵌套的,我使用的是python 2.7
字幕理解如何?
filtered_dict = {k:v for k,v in d.iteritems()if filter_string in k}
一个你看到它,它应该是不言自明的,因为它看起来像英文很好
此语法需要Python 2.7或更高版本。
在Python 3中,只有 dict.items()
,而不是code> iteritems()所以你可以使用:
filtered_dict = {k:v for (k,v)in d.items()if filter_string in k}
I'm a C coder developing something in python. I know how to do the following in C (and hence in C-like logic applied to python), but I'm wondering what the 'Python' way of doing it is.
I have a dictionary d, and I'd like to operate on a subset of the items, only those who's key (string) contains a specific substring.
i.e. the C logic would be:
for key in d:
if filter_string in key:
# do something
else
# do nothing, continue
I'm imagining the python version would be something like
filtered_dict = crazy_python_syntax(d, substring)
for key,value in filtered_dict.iteritems():
# do something
I've found a lot of posts on here regarding filtering dictionaries, but couldn't find one which involved exactly this.
My dictionary is not nested and i'm using python 2.7
How about a dict comprehension:
filtered_dict = {k:v for k,v in d.iteritems() if filter_string in k}
One you see it, it should be self-explanatory, as it reads like English pretty well.
This syntax requires Python 2.7 or greater.
In Python 3, there is only dict.items()
, not iteritems()
so you would use:
filtered_dict = {k:v for (k,v) in d.items() if filter_string in k}
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