Python字典创建语法 [英] Python dictionary creation syntax

问题描述

我想知道是否有任何方法来填充字典，以便您将多个键映射到相同的值，而不是说如下：

  d = {1：'yes'，2：'yes'，3：'yes'，4：'no'} 
  

我正在考虑以下几点：

  d = {* （1,2,3）：'yes'，4：'no'} 
  

一个语法错误。

有没有一个相当简单的方法来做这个没有TOO很多的混淆？ （我不打代码高尔夫球，但是我也不需要一遍又一遍地编写基本上相同的东西，但是代码高尔夫球的相关答案也是不错的，因为代码高尔夫是awesome =]）。 / p>

修改：

我可能选择了一个不好的例子。这是我想要做的：

  d = {*（'READY'，95）：'GPLR2_95' 'CHARGING'：'GPLR3_99'，'PROTECTION'：'GPLR3_100'，'CONNECTED'：'GPLR3_101'，'ERROR'：'GPLR3_102'} 
  

我希望这样扩展到：

  d = {'READY '：'GPLR2_95'，95：'GPLR2_95'，...} 
  

>编辑：

我知道这是愚蠢的，完全不必要的，但我的目标是将这个声明放在一行上。这显然不应该限制任何回应和编写代码，只因为它符合1行是愚蠢的。但是我正在写一个模块级常数，如果它是一个班轮，这将是很好的。

解决方案

你可以把它周围：

 >>> d1 = {是：[1,2,3]，否：[4]} 
  

然后转换该字典：

 >>> d2 = {value：键中的键，用于d1 [key]}中的值
>>>> d2 
 {1：'yes'，2：'yes'，3：'yes'，4：'no'} 
  

I'm wondering if there's any way to populate a dictionary such that you have multiple keys mapping to the same value that's less verbose than say:

d = {1:'yes', 2:'yes', 3:'yes', 4:'no'}

I'm thinking something along the lines of:

d = {*(1,2,3):'yes', 4:'no'}

which is obviously a syntax error.

Is there a reasonably simple method of doing this without TOO much obfuscation? (I'm not playing code golf, but I also don't need to write essentially the same thing over and over. However, any code-golf related answers would be appreciated as well since code-golf is awesome =]).

Edit:

I probably picked a bad example. This is what I'm trying to do:

d = {*('READY', 95): 'GPLR2_95', 'CHARGING': 'GPLR3_99', 'PROTECTION': 'GPLR3_100', 'CONNECTED': 'GPLR3_101', 'ERROR':'GPLR3_102'}

What I would expect this to expand to is:

d = {'READY':'GPLR2_95', 95: 'GPLR2_95', ...}

Edit->Edit:

I know this is stupid and totally unnecessary, but my goal is to make this declaration on a single line. This obviously shouldn't limit any responses and writing code just because it fits on 1 line is stupid. But I'm writing a module level constant dict that would be nice if it was a single liner.

解决方案

You could turn it around:

>>> d1 = {"yes": [1,2,3], "no": [4]}

and then "invert" that dictionary:

>>> d2 = {value:key for key in d1 for value in d1[key]}
>>> d2
{1: 'yes', 2: 'yes', 3: 'yes', 4: 'no'}

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