在字典Javascript中找到多个关键词 [英] find multiple key words within a dictionary Javascript

问题描述

我正在尝试执行一个字典查看一些内容，我的方法到目前为止，我只能查找单个单词，因为我正在使用拆分（''）方法在空间上分裂。我刚刚碰到一个堵塞，并且想知道你们有没有坚实的输入。就像我在我的字典中有两个字的钥匙怎么办？像下面的

  var dictionary = {Darth Vader：坏屁股父亲，卢克：坏的儿子屁股，
天行者：一些绝地骑士的姓氏，卢克天空之王：坏屁股的儿子} 
  

这是我到目前为止的代码，它对于单个词显然不是muliplte关键词。 getElementsByClassName是一个返回所有类的数组的函数。

  var body ='< div class =activity-inner >这是一个测试词汇表部分，用于测试星球大战词汇表的亮点。像Luke Skywalker和Darth Vader，Luke和Skywalker。 < / DIV> < div class =activity-inner> Hello glossary again Luke Skywalker Darth Vader< / div>'; 
 document.write（body）; 
 var matches = getElementsByClassName（activity-inner）; （int i = 0; i< matches.length; i ++;）{
 var content = matches [i] .innerHTML; 
 
 document.write（content）; 
 var words = content.split（''）; （var j = 0; j< words.length; j ++）{
 
 
 
 {var b = \w\s] | _ / g，）
 .replace（/ \s + / g，）.toLowerCase（）; 
 if（temp in dictionary）{
 words [j] =< span class ='highlight'style ='color：green;'>+ words [j] +跨度>中; 
} 
 document.write（words [j] +< br />）; 
 
 
 
} 
 body = words.join（''）; 
 document.write（< br />< br />+ body）; 
} 
  

上面的例子不行。然而，我的字典中的一些事情会是这样的。我应该怎么做，如果可能的话也可以避免这种情况？谢谢！

解决方案

构造一个RegEx，由字典的所有键组成（以防再次替换替换）。然后，使用 String.replace（pattern，replace_function），如下所示。

演示： http://jsfiddle.net/Z7DqF/

  //示例
 var dictionary = {Darth Vader：坏屁股父亲，卢克：坏屁股的儿子，
 天行者：绝地骑士之姓，路加福音，坏屁股之子} 
 content =....; 
 
 var pattern = []，
 key; 
（键入字典）{
 //消除密钥，并将其推送到列表中
 pattern.push（key.replace（/（[[^ $。 （）{}]）/ g，'\\ $ 1'））; 
} 
 pattern =（？：+ pattern.join（）|（?:）+）; // Create pattern 
 pattern = new RegExp（pattern，g）; 
 
 //遍历字符串，并替换每一次匹配的令牌
 content = content.replace（pattern，function（full_match）{
 return dictionary [full_match]; 
}）; 
  

I am trying to perform a dictionary look up on some content and my approach so far I can only look up single words because I am using the split(' ') method splitting on just the space. I just ran into a sorta blockage and was wondering if guys you had any solid input. like what if I have keys in my dictionary that are of two words. Like below

var  dictionary = { "Darth Vader" : "Bad Ass Father", "Luke": "Son of the Bad Ass",
"Skywalker" : "Last name of some Jedi Knights", "Luke SkyWalker" : "Son of the Bad Ass"} 

this is the code I got so far and it works for single words obviously but not muliplte key words. getElementsByClassName is a function to return an array of all classes found.

var body = '<div class="activity-inner"> This is a test glossary body paragraph to test glossary highlight of the Star Wars vocabulary. like Luke Skywalker and Darth Vader, Luke and Skywalker. </div> <div class="activity-inner">Hello glossary again here Luke Skywalker Darth Vader</div>';
document.write( body);
var matches = getElementsByClassName("activity-inner");
for (int i = 0; i < matches.length; i++;) {
var content = matches[i].innerHTML;
document.write(content);
var  words = content.split(' ');



for (var j = 0; j < words.length; j++) {
var temp = words[j].replace(/[^\w\s]|_/g, "")
     .replace(/\s+/g, " ").toLowerCase();
 if (temp in dictionary) {
words[j] = "<span class='highlight' style='color:green;'>"+words[j]+"</span>";
}
document.write(words[j] +"<br />");



}
body = words.join(' ');
document.write( "<br /> <br />" + body);
}

The above example wouldn't work. However Some of the things in my dictionary are gonna be like this. How should I go about this and maybe avoid case as well if at all possible? Thanks!

解决方案

Construct a RegEx, consisting of all keys of the dictionary (to prevent a replacement from being replaced again). Then, use String.replace(pattern, replace_function) as shown below.

Demo: http://jsfiddle.net/Z7DqF/

// Example
var dictionary = { "Darth Vader" : "Bad Ass Father", "Luke": "Son of the Bad Ass",
"Skywalker" : "Last name of some Jedi Knights", "Luke SkyWalker" : "Son of the Bad Ass"}
    content = "....";

var pattern = [],
    key;
for (key in dictionary) {
    // Sanitize the key, and push it in the list
    pattern.push(key.replace(/([[^$.|?*+(){}])/g, '\\$1'));
}
pattern = "(?:" + pattern.join(")|(?:") + ")"; //Create pattern
pattern = new RegExp(pattern, "g");

// Walk through the string, and replace every occurrence of the matched tokens
content = content.replace(pattern, function(full_match){
    return dictionary[full_match];
});

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