如何比较字典，看看有什么变化？ [英] How to compare dictionaries and see what changed?

问题描述

1. self.new_port_dict = {} ＃存储新端口的字典
   从curr_host


2. self.old_port_dict = {} ＃字典到存储旧的端口from old_host


3. self.results_ports_dict = {} ＃保存更改/新增端口的结果

I am having 3 dictionaries in my python code :

脚本需要比较哪些端口更改，我几乎在那里只是无法提供帮助我：

1. self.new_port_dict = {} # Dictionary to store the new ports from curr_host
2. self.old_port_dict = {} # Dictionary to store the old ports from old_host
3. self.results_ports_dict = {} # Holds the result of changed/newly added ports

The script needs to compare what port changed, I am almost there just unable to present help me out : 

这样输出为：

This gives a output as :

你可以清楚地看到，我也有结果改变的字典。我想打印：

The following Host/ports were available in old scan : !! {'172.16.0.41': set([(80, 'tcp'), (666, 'tcp')]), '172.16.0.163': set([(80, 'tcp'), (22, 'tcp')])} -------------------------------------------------------- The following Host/ports have been added in new scan: !! {'172.16.0.41': set([(80, 'tcp'), (22, 'tcp')]), '172.16.0.163': set([(80, 'tcp'), (22, 'tcp')])} Result Change: for 172.16.0.41 -> set([(22, 'tcp')]) From set([(80, 'tcp'), (666, 'tcp')]) Result Change: for 172.16.0.163 -> set([]) From set([(80, 'tcp'), (22, 'tcp')])

As you can clearly see , I have the resulting changed dictionary as well. I want to just print :

推荐答案

我相信你没有比较字典，但实际上是与密钥相对应的值。

解决方案

这里的基本想法是：

• 主持人不得总是存在于过去和现在的扫描中，避免使用 collections.defaultdict ，以确保即使在没有主机的情况下也可以直接比较值。因为缺少键的值将被自动生成（空的集）

The basic ideas here are:

在设置之间有3个操作

Have 3 operations on the set of ports

old - new ：查看哪些端口在旧扫描中，但不再在新的（已删除端口）中

old - new: to see which ports were in the old scan but no longer in the new (deleted ports)

new - old ：查看哪些端口在新扫描中，但不在旧（添加端口）中

new - old: to see which ports are in the new scan but were not in the old (added ports)

有几种方法可以将代码移动到优化中，但我想这点更清晰

There are several ways to move the code around to optimize, but I guess the point is much more clarity.

希望它有帮助

import collections

scan0 = collections.defaultdict(set, {
    '172.16.0.41': set([(80, 'tcp'), (666, 'tcp')]),
    '172.16.0.163': set([(80, 'tcp'), (22, 'tcp')])
})

scan1 = collections.defaultdict(set, {
    '172.16.0.41': set([(80, 'tcp'), (22, 'tcp')]),
    '172.16.0.163': set([(80, 'tcp'), (22, 'tcp')])
})

hosts = sorted(set(scan0.keys() + scan1.keys()))


scan_same = dict()
scan_new = dict()
scan_del = dict()

for host in hosts:
    scan_same[host] = scan0[host] & scan1[host]
    scan_new[host] = scan1[host] - scan0[host]
    scan_del[host] = scan0[host] - scan1[host]

print()
print('-' * 10, 'Same')
for host, ports in scan_same.items():
    print(host, ':')
    for port in ports:
        print(':::', port[0], '/', port[1])
print()
print('*' * 10, 'Added')
for host, ports in scan_new.items():
    print(host, ':')
    for port in ports:
        print(':::', port[0], '/', port[1])

print()
print('=' * 10, 'Deleted')
for host, ports in scan_del.items():
    print(host, ':')
    for port in ports:
        print(':::', port[0], '/', port[1])

这将输出：

---------- Same
172.16.0.163 :
::: 80 / tcp
::: 22 / tcp
172.16.0.41 :
::: 80 / tcp

*********** Added
172.16.0.163 :
172.16.0.41 :
::: 22 / tcp

========== Deleted
172.16.0.163 :
172.16.0.41 :
::: 666 / tcp

这篇关于如何比较字典，看看有什么变化？的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！