混合列表和Python中的Dict [英] Mixing List and Dict in Python

问题描述

我想知道如何在Python上混合列表和dict？我知道PHP，我可以这样做：

  $ options = array（
option1，
option2，
option3=>数组（meta1，meta2，meta3），
option4
） 
  

问题是python对于不同的列表有不同的括号。 （）for tuple，[] for list，{} for dict。似乎没有什么办法混合使用，我不断收到语法错误。

我现在使用的是python 2.7。请指导如何正确执行。

非常感谢，

Rufas

更新1：

我会稍微详细说明我要做的事情。我想在这里写一个简单的python脚本来做一些API请求：

http://www.diffbot.com/products/automatic/article/

相关部分是字段查询参数。它是像...& fields = meta，querystring，images（url，caption）...等等。所以上面的数组可以写成（在PHP中）

  $ fields = array（
'meta'，
'querystring'，
'images'=>数组（'url'，'caption'）
）; 
  

$字段将被传递给一个处理方法。结果将返回，如下所示：

  $ json = diffbot-> get（article，$ url，$字段）; 
  

事情是 - 我在PHP中没有问题，但是当我尝试写在Python中，事情不像看起来那么容易...

解决方案

我很确定有3个答案我的问题，当它收到一票，它是最接近我想要的。现在很奇怪，当我想选择一个接受答案时，它已经消失了：（

要概述，删除的答案表明我应该这样做：

  options = [
option1，
option2，
 { option3：[meta1，meta2，meta3]}，
option4
] 
  

这样很适合我想要处理的列表中的每个项目，我只是循环遍历所有的值并检查它的类型，如果是一个字符串，处理它像正常，但是当它是一个dict / list，它会被不同的处理。

最终，我设法让它工作，我得到了我想要的。

特别感谢Igor Chubin和Hyperboreus为我提供建议和想法，以测试和发现我一直在寻找的答案。非常感谢。

谢谢！

Rufas

I was wondering how do you mix list and dict together on Python? I know on PHP, I can do something like this:

$options = array(
    "option1", 
    "option2", 
    "option3" => array("meta1", "meta2", "meta3"), 
    "option4" 
);

The problem is python have different bracket for different list. () for tuple, [] for list, and {} for dict. There don't seems to be any way to mix them and I'm keep getting syntax errors.

I am using python 2.7 now. Please advice how to do it correctly.

Much thanks,

Rufas

Update 1:

I'll slightly elaborate what I'm trying to do. I am trying to write a simple python script to do some API requests here:

http://www.diffbot.com/products/automatic/article/

The relevant part is the fields query parameters. It is something like ...&fields=meta,querystring,images(url,caption)... . So the above array can be written as (in PHP)

$fields = array(
    'meta',
    'querystring',
    'images' => array('url', 'caption')
);

And the $fields will be passed to a method for processing. The result will be returned, like this:

$json = diffbot->get("article", $url, $fields);

The thing is - I have no problem in writing it in PHP, but when I try to write it in Python, the thing is not as easy as it seems...

解决方案

I'm pretty sure there are 3 answers for my question and while it received a -1 vote, it is the closest to what I want. It is very strange now that it is gone when I want to pick that one up as "accepted answer" :(

To recap, the removed answer suggest I should do this:

options = [
    "option1", 
    "option2", 
    {"option3":["meta1", "meta2", "meta3"]}, 
    "option4" 
]

And that fits nicely how I want to process each item on the list. I just loop through all values and check for its type. If it is a string, process it like normal. But when it is a dict/list, it will be handled differently.

Ultimately, I managed to make it work and I get what I want.

Special thanks to Igor Chubin and Hyperboreus for providing suggestions and ideas for me to test and discover the answer I've been looking for. Greatly appreciated.

Thank you!

Rufas

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