Python - 将列表添加到dict（初学者） [英] Python--adding list into dict (beginner)

问题描述

我非常新的编程（现在我的第一堂课），所以承担我的格式问题和误会，或错过简单的修复。

我有一个带有推文数据的dict：'user'作为键，然后是'text'作为它们的值。我的目标是找到他们回复另一个用户的推文，以@符号开头，然后再创建一个包含作者的用户和他回复的所有用户的新的dict。这是我以下相当简单的if语句。我也可以使用split函数隔离他们正在回复的人的用户名（该函数将@符号和之后的下一个空格中的所有文本）。

$ b $ a，b，c，d，e中的t为


en =''
task1dict = {}
，f，g，h，i，j，k，l，m，n：
如果t ['text'] [0] =='@'：
user = t ['user' ]
repliedto = t ['text']。split（st）[ - 1] .split（en）[0]
task1dict [user] = [repliedto]

Username1回复到username2。用户名2回复了username3和username5。

我正在尝试创建一个可以读取以下内容的dict（caled tweets1）：

 'user'：'repliedto'
 username1：[username2] 
 username2：[username3，username5] 
  

等。

有没有更好的方法隔离用户名，然后把它们成为一个新的字典？以下是tweet数据的2个条目示例：

  {user：datageek88，text：@ sundevil1992好的问题！@joeclarknet这是考试吗？}，
 {user：joeclarkphd，文本：考试问题将在适当的时候回答@ sundevil1992} 
  

我现在可以将其添加到一个dict，但它只会为每个用户保存一个repliedto，所以而不是显示username2已经回复了3和5，它只显示最新的一个，5：

  {'username1' ['username2']，
'username2'：['username5']} 
  

如果我在这里做任何一个严肃的no-no，我很抱歉，请告诉我我在做错什么！

解决方案

我可能会这样做。使用以下正则表达式来标识所有用户名。

  r@（[^ \s] *）
  pre> 
 
 
它意味着寻找 @ 符号，然后返回所有不是空格的字符。一个 defaultdict 是一个简单的字典，如果找不到键，则返回默认值。在这种情况下，在我们添加新密钥的情况下，我指定一个空的集合作为返回类型。
  import re 
 from collections import defaultdict 
 tweets = [{user：datageek88，text：@ sundevil1992 good question！@joeclarknet Is这个考试？}，
 {user：joeclarkphd，text：考试问题将在适当时候回答@ sundevil1992}] 
 
 from_to = defaultdict （设置）
在tweet中的推文：
如果@in tweet ['text']：
 user = tweet ['user'] 
 for replied_to in re.findall （r@（[^ \s] *），tweet ['text']）：
 from_to [user] .add（replied_to）
 
 print from_to 
  
 
 
 
输出
 
 
 
  defaultdict（< type'list'> {'joeclarkphd'：['sundevil1992']，
'datageek88'：['sundevil1992'，'joeclarknet']}）
  
 
I'm very new to programming (taking my first class in it now), so bear with me for format issues and misunderstandings, or missing easy fixes.

I have a dict with tweet data: 'user' as keys and then 'text' as their values. My goal here is to find the tweets where they are replying to another user, signified by starting with the @ symbol, and then make a new dict that contains the author's user and the users of everyone he replied to. That's the fairly simple if statement I have below. I was also able to use the split function to isolate the username of the person they are replying to (the function takes all the text between the @ symbol and the next space after it).
st='@'
en=' '
task1dict={}
for t in a,b,c,d,e,f,g,h,i,j,k,l,m,n:
    if t['text'][0]=='@':
        user=t['user']
        repliedto=t['text'].split(st)[-1].split(en)[0]
        task1dict[user]=[repliedto]
Username1 replied to username2. Username2 replied to both username3 and username5.

I am trying to create a dict (caled tweets1) that reads something like:
'user':'repliedto'
username1:[username2]
username2:[username3, username5]
etc.

Is there a better way to isolate the usernames, and then put them into a new dict? Here's a 2 entry sample of the tweet data:
{"user":"datageek88","text":"@sundevil1992 good question! @joeclarknet Is this on the exam?"},
{"user":"joeclarkphd","text":"Exam questions will be answered in due time @sundevil1992"}
I am now able to add them to a dict, but it would only save one 'repliedto' for each 'user', so instead of showing username2 have replied to both 3 and 5, it just shows the latest one, 5:
{'username1': ['username2'],
'username2': ['username5']}
Again, if I'm making a serious no-no anywhere in here, I apologize, and please show me what I'm doing wrong!
解决方案
I might do it like this.  Use the following regular expression to identify all usernames.  
r"@([^\s]*)"
It means look for the @ symbol, and then return all characters that aren't a space. A defaultdict is a simply a dictionary that returns a default value if they key isn't found.  In this case, I specify an empty set as the return type in the event that we are adding a new key.
import re
from collections import defaultdict
tweets = [{"user":"datageek88","text":"@sundevil1992 good question! @joeclarknet Is this on the exam?"},
{"user":"joeclarkphd","text":"Exam questions will be answered in due time @sundevil1992"}]

from_to = defaultdict(set)
for tweet in tweets:
    if "@" in tweet['text']:
        user = tweet['user']
        for replied_to in re.findall(r"@([^\s]*)", tweet['text']):
            from_to[user].add(replied_to)

print from_to


Output

defaultdict(<type 'list'>, {'joeclarkphd': ['sundevil1992'], 
'datageek88': ['sundevil1992', 'joeclarknet']})


                        
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