存储路径到字典值 [英] Store path to dictionary value

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本文介绍了存储路径到字典值的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

如何将路径存储在 dict dict 中的值?例如,我们可以轻松地将路径存储在变量 name_field 中的名称中:

  person = {} 
person ['name'] ='Jeff Atwood'
person ['address'] = {}
person ['address'] ['street'] ='Main Street'
person ['address'] ['zip'] ='12345'
person ['address'] [ 'city'] ='迈阿密'

#获取名称
name_field ='name'
print(person [name_field])

如何存储 city 值的路径?

 #获取城市
city_field = ['地址','城市']
打印(person [city_field])//显然赢得'工作!


解决方案

您可以使用 / code>函数做这个

  print reduce(lambda x,y:x [y],city_field,person )

输出



迈阿密


How might one store the path to a value in a dict of dicts? For instance, we can easily store the path to the name value in a variable name_field:

person = {}
person['name'] = 'Jeff Atwood'
person['address'] = {}
person['address']['street'] = 'Main Street'
person['address']['zip'] = '12345'
person['address']['city'] = 'Miami'

# Get name
name_field = 'name'
print( person[name_field] )

How might the path to the city value be stored?

# Get city
city_field = ['address', 'city']
print( person[city_field] )  // Obviously won't work!

解决方案

You can use reduce function to do this

print reduce(lambda x, y: x[y], city_field, person)

Output

Miami

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