将值从txt文件转换为字典 [英] convert list of values from a txt file to dictionary

问题描述

所以我有这个名为students.txt的txt文件，我想定义一个名为load（student）
的函数，所以我有这个代码：

So i have this txt file called "Students.txt", I want to define a function called load(student) so i have this code:

def load(student):
      body

我不太确定要为代码正文写什么，以便它读取文件并从文件中返回值作为字典。我知道这会像readlines（）
，文件students.txt看起来像这样：

im not quite sure what to write for the body of code so that it reads the file and returns the value from the file as dictionary. I know it would be something like readlines() anyway, the file students.txt looks like this:

P883, Michael Smith, 1991
L672, Jane Collins, 1992
(added)L322, Randy Green, 1992
H732, Justin Wood, 1995(added)
^key  ^name        ^year of birth 

该函数必须作为字典返回，如下所示：

the function has to return as a dictionary that looks like this:

{'P883': ('Michael Smith',1991),
'(key)':('name','year')}

我设法通过尝试和错误返回值，但是我不能创建新行并保留返回\\\
。

I managed to return the values by trial and error however i cant make new lines and keep returning \n.

===============
这个问题已经回答了，我使用了以下代码，但是，在txt文件中的值中有一个空格（参见添加的部分）它不再工作，并给出一个错误，表示列表索引超出范围

=============== this question has been answered and i used the following code which works perfectly however when there is a space in the values from the txt file.. (see added parts) it doesnt work anymore and gives an error saying that list index is out of range

推荐答案

这样做应该这样做，我想：

Something like this should do it, I think:

students = {}

infile = open("students.txt")
for line in infile:
  line = line.strip()
  parts = [p.strip() for p in line.split(",")]
  students[parts[0]] = (parts[1], parts[2])

这可能不是100％，但应该给你一个起点。为简洁起见，省略错误处理。

This might not be 100%, but should give you a starting-point. Error handling was omitted for brevity.

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