词典中的访问功能第2部分 [英] Access Functions in Dictionary Part 2

问题描述

作为此问题的后续行动：
我有2个功能看起来像这样：

As a follow-up to this question: I have 2 functions that look like this:

def abc(a,b):
    return a+b

def cde(c,d):
    return c+d

而且想要将它分配给这样的字典：

And I want to assign it to a dictionary like this:

functions = {'abc': abc(a,b), 'cde': cde(c,d)}

我可以这样做，但是会在'cde '：

I could do this, but it would break at 'cde':

functions = {'abc':abc, 'cde':cde}

functions_to_call = ['abc', 'cde']
for f in functions_to_call:
    a, b = 3, 4
    c, d = 1, 2
    if f in functions:
       functions[f](a, b)

另外，如果cde有3个参数呢？

Also, what if cde took 3 arguments?

推荐答案

使用 args 的单独序列，并使用splat运算符 * ）：

Make a seperate sequence of args and use the splat operator (*):

>>> def ab(a,b):
...   return a + b
... 
>>> def cde(c,d,e):
...   return c + d + e
... 
>>> funcs = {'ab':ab, 'cde':cde}
>>> to_call = ['ab','cde']
>>> args = [(1,2),(3,4,5)]
>>> for fs, arg in zip(to_call,args):
...   print(funcs[fs](*arg))
... 
3
12

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