将一个值映射到具有公共关系Scala的所有值 [英] Map one value to all values with a common relation Scala

问题描述

拥有一组数据：

  {sentenceA1} {\t} {sentenceB1} 
 {sentenceA1 } {\t} {sentenceB2} 
 {sentenceA2} {\t} {sentenceB1} 
 {sentenceA3} {\t} {sentenceB1} 
 {sentenceA4} {\t我想将一个句子A映射到Scala中有一个常见句子B的所有句子。所以结果将是这样的：
  {sentenceA1}  - > {sentenceA2，sentenceA3，sentenceA4}或
 
 {sentenceA2}  - > {sentenceA1，sentenceA3} 
  
 
 
解决方案
 
  val lines = List（
sentenceA1\tsentenceB1，
sentenceA1\tsentenceB2，
sentenceA2\tsentenceB1 ，
sentenceA3\tsentenceB1，
sentenceA4\tsentenceB2
）
 
 val afterSplit = lines.map（_。split（\ t 
 
 
 val ba = afterSplit 
 .groupBy（_（1））
 .mapValues（_。map（_（0）））
 
 val ab = afterSplit 
 .groupBy（_（0））
 .mapValues（_。map（_（1）））
 
 val result = ab.map {case a，b）=> 
 a  - > b.foldLeft（Set [String]（））（_ ++ ba（_））。diff（Set（a））
} 
  
 
Having a set of data: 
{sentenceA1}{\t}{sentenceB1}  
{sentenceA1}{\t}{sentenceB2}  
{sentenceA2}{\t}{sentenceB1}   
{sentenceA3}{\t}{sentenceB1}   
{sentenceA4}{\t}{sentenceB2}    
I want to map a sentenceA to all the sentences that have a common sentenceB in Scala so the result will be something like this:
{sentenceA1}->{sentenceA2,sentenceA3,sentenceA4} or  

{sentenceA2}->{sentenceA1, sentenceA3}

解决方案
val lines = List(
  "sentenceA1\tsentenceB1",
  "sentenceA1\tsentenceB2",
  "sentenceA2\tsentenceB1",
  "sentenceA3\tsentenceB1",
  "sentenceA4\tsentenceB2"
)

val afterSplit = lines.map(_.split("\t"))

val ba = afterSplit
  .groupBy(_(1))
  .mapValues(_.map(_(0)))

val ab = afterSplit
  .groupBy(_(0))
  .mapValues(_.map(_(1)))

val result = ab.map { case (a, b) =>
  a -> b.foldLeft(Set[String]())(_ ++ ba(_)).diff(Set(a))
}


                        
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