在列表中找到最小值 [英] Finding minimum values in a list of dicts

问题描述

  l = [{'dist'：56，'responder'： N}，{'dist'：26，'responder'：N}，{'dist'：86，'responder'：N}] 
  

我想要返回2个最小距离（'dist'）以及responder的值，在Python中最好的方法是什么？

解决方案

使用@ Bakuriu的解决方案修改：

  l = [{'dist'：56，'responder'：'n'}，{'dist'：26，'responder'：'n'}，\ 
 {' dist'：86，'responder'：'n'}] 
 
 minimumTwo = sorted（l，key = lambda d：d ['dist']）[：2] 
  

输出：

  {'responder'：'n'，'dist'：26}，{'responder'：'n'，'dist'：56}] 
  




If I have a list of dicts like:

l = [{'dist':56, 'responder':N}, {'dist':26, 'responder':N}, {'dist':86, 'responder':N}]

And I want to return the 2 smallest distances ('dist') as well as the value for 'responder', what is the best way to do that in Python?

解决方案

Using @Bakuriu's solution with a modification:

l = [{'dist':56, 'responder':'n'}, {'dist':26, 'responder':'n'}, \
{'dist':86, 'responder':'n'}]

smallestTwo = sorted(l, key=lambda d: d['dist'])[:2]

Output:

[{'responder': 'n', 'dist': 26}, {'responder': 'n', 'dist': 56}]

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