将列表列表列入列表的字典 [英] Turning a list of lists into a dictionary of lists
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问题描述
我希望将列表列表转换为字典,其中键指向列表的原始列表中的列表位置,并且值是列表中的项目列表(从原始列表中列表)。我也希望删除原始列表中的所有Nones。例如:
[[(1,None),(2,None)],[(0,None) 2,无)],[(1,无),(0,无)]]
将要成为:
{0:[1,2],1:[0,2],2: 1,0]}
解决方案
列表理解
raw = [[(1,无),(2,无)],[(0,无) (2,无)],[(1,无),(0,无)]]
print {i:[el [0] for el in l] for i,l in enumerate(raw)}
打印
{0:[1,2],1:[0,2],2:[1,0]}
Hi there I am having a small problem with a code I am trying to implement. I wish to convert a list of lists into a dictionary where the keys refer to the lists position in the original list of lists, and the values are a list of the items that were in said list (from the original list of lists). I also wish to remove all of the Nones present in the original list of lists. For example:
[[(1, None), (2, None)], [(0, None), (2, None)], [(1, None), (0, None)]]
I would want this to become:
{0: [1, 2], 1: [0, 2], 2: [1, 0]}
解决方案
Looks like a basic dict and list comprehension
raw = [[(1, None), (2, None)], [(0, None), (2, None)], [(1, None), (0, None)]]
print {i: [el[0] for el in l] for i, l in enumerate(raw)}
prints
{0: [1, 2], 1: [0, 2], 2: [1, 0]}
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