读取python dict或yaml，并将其称为Python参数和对象的python函数 [英] Read python dict or yaml and call as python function with arguments and objects

问题描述

要阅读以下python dict或其等效的yaml并生成等效的python函数调用

To read the below python dict or its equivalent yaml and generate equivalent python function call

mydict = {'RouteAdd': {'route_config': {'RouteConfig': {'table_name': 'my table', 'app_id': 'my app', 'nexthops': [{'NexthopInfo': {'nexthop_index': 2, 'nexthop_address': {'GatewayAddress': {'ethernet_mac': 'my mac', 'nexthop_ip': 'my ip'}}, 'if_name': 'my interface'}}]}}}}

它的yaml（为了可读性）：

Its yaml(for readability):

RouteAdd:
  route_config:
    RouteConfig:
      app_id: "my app"
      nexthops:
      - NexthopInfo:
          if_name: "my interface"
          nexthop_address:
            GatewayAddress:
              ethernet_mac: "my mac"
              nexthop_ip: "my ip"
          nexthop_index: 2
      table_name: "my table"

d喜欢阅读上述的yaml或python dict，并调用如下：

I would like to read the above kind of yaml or python dict and call as below:

RouteAdd(route_config=Routeconfig(app_id="my app",nexthops=[NexthopInfo(if_name="my interface",nexthop_address=GatewayAddress(ethernet_mac="my mac",nexthop_ip="my ip"),nexthop_index=2)],table_name="my table"))

基本上替代层次结构是一个对象。我粘贴的是一个小剪辑。寻找一个递归函数，通过读取yaml或python dict并将其转换为上述格式，以便我可以调用和执行该函数。任何帮助深表感谢。谢谢

Basically alternate hierarchy is an object. What I have pasted is a small clip. Looking for a recursive function that does this by reading either a yaml or python dict and convert it to above format so that I can call and execute the function. Any help is much appreciated. Thanks

推荐答案

尝试这样：

def call_dict(d):
    k, v = list(d.items())[0]  # ('RouteAdd', {route_config: ...})
    kwargs = {}
    for k2, v2 in v.items():
        if isinstance(v2, dict):
            kwargs[k2] = call_dict(v2)
        elif isinstance(v2, list):
            kwargs[k2] = [(call_dict(v3) if isinstance(v3, dict) else v3) for v3 in v2]
        else:
            kwargs[k2] = v2
    return globals()[k](**kwargs)

测试：

def test1(t_arg=None, t_arg2=None):
    return t_arg + sum(t_arg2)

def test2(t_arg=None):
    return t_arg


res = test1(t_arg=1, t_arg2=[test2(t_arg=2), test2(t_arg=3)])
print(res)  # 6


test_dict = {
    'test1': {
        't_arg': 1,
        't_arg2': [
            {'test2': {'t_arg': 2}},
            {'test2': {'t_arg': 3}},
        ]
    }
}

res = call_dict(test_dict)
print(res)  # 6

更新：

作为代码字符串：

def str_of_code(d):
    k, v = list(d.items())[0]
    kwargs = {}
    for k2, v2 in v.items():
        if isinstance(v2, dict):
            kwargs[k2] = str_of_code(v2)
        elif isinstance(v2, list):
            kwargs[k2] = '[{}]'.format(', '.join(
                (str_of_code(v3) if isinstance(v3, dict) else repr(v3)) for v3 in v2)
            )
        else:
            kwargs[k2] = repr(v2)
    return '{}({})'.format(k, ', '.join('{}={}'.format(*i) for i in kwargs.items()))


test_dict = {
    'test1': {
        't_arg': 1,
        't_arg2': [
            {'test2': {'t_arg': 2}},
            {'test2': {'t_arg': 3}},
        ]
    }
}

res = str_of_code(test_dict)
print(res)  # test1(t_arg=1, t_arg2=[test2(t_arg=2), test2(t_arg=3)])

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