在python中只分割列表的一部分 [英] Split only part of list in python

问题描述

我有一个列表

['Paris, 458 boulevard Saint-Germain', 'Marseille, 29 rue Camille Desmoulins', 'Marseille, 1 chemin des Aubagnens']

我想要关键字boulevard，rue，chemin 像输出

i want split after keyword "boulevard, rue, chemin" like in output

['Saint-Germain', 'Camille Desmoulins', 'des Aubagnens']

感谢您的时间

推荐答案

它不工作，因为你只是在分裂后提取一个单词：

It's not working because you are only extracting one word after you split:

adresse = [i.split(' ', 8)[3] for i in my_list`]

由于 3] 。

尝试 [3：] 。啊，但是这还不够，因为当你想要一个字符串列表时，你会得到一个列表列表。所以你还需要使用 join 。

Try [3:] instead. Ah, but that still won't be enough, because you'll get a list of lists, when you want a list of strings. So you also need to use join.

adresse = [' '.join(i.split(' ', 8)[3:]) for i in my_list`]

现在你唯一的困难是处理不规则的街道地址，例如没有房屋号码的人，或街头名字的几个字。我没有解决办法！

Now your only difficulty is dealing with irregular street addresses, e.g. people who don't have a house number, or several words in the street name. I have no solution for that!

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