使用php中的opendir（）按字母顺序排列和显示目录列表 [英] Sort and display directory list alphabetically using opendir() in php

问题描述

php noob这里 - 我拼凑在一起这个脚本来显示一个包含opendir的文件夹中的图像列表，但是我无法找出按字母顺序排列数组的方式（或在哪里）

php noob here - I've cobbled together this script to display a list of images from a folder with opendir, but I can't work out how (or where) to sort the array alphabetically

<?php

// opens images folder
if ($handle = opendir('Images')) {
while (false !== ($file = readdir($handle))) {

// strips files extensions  
$crap   = array(".jpg", ".jpeg", ".JPG", ".JPEG", ".png", ".PNG", ".gif", ".GIF", ".bmp", ".BMP", "_", "-");    

$newstring = str_replace($crap, " ", $file );   

//asort($file, SORT_NUMERIC); - doesnt work :(

// hides folders, writes out ul of images and thumbnails from two folders

    if ($file != "." && $file != ".." && $file != "index.php" && $file != "Thumbnails") {
    echo "<li><a href=\"Images/$file\" class=\"thickbox\" rel=\"gallery\" title=\"$newstring\"><img src=\"Images/Thumbnails/$file\" alt=\"$newstring\" width=\"300\"  </a></li>\n";}
}
closedir($handle);
}

?>

任何建议或指针都将不胜感激！

Any advice or pointers would be much appreciated!

推荐答案

您需要先将文件读入数组，然后再排序。这个怎么样？

You need to read your files into an array first before you can sort them. How about this?

<?php
$dirFiles = array();
// opens images folder
if ($handle = opendir('Images')) {
    while (false !== ($file = readdir($handle))) {

        // strips files extensions      
        $crap   = array(".jpg", ".jpeg", ".JPG", ".JPEG", ".png", ".PNG", ".gif", ".GIF", ".bmp", ".BMP", "_", "-");    

        $newstring = str_replace($crap, " ", $file );   

        //asort($file, SORT_NUMERIC); - doesnt work :(

        // hides folders, writes out ul of images and thumbnails from two folders

        if ($file != "." && $file != ".." && $file != "index.php" && $file != "Thumbnails") {
            $dirFiles[] = $file;
        }
    }
    closedir($handle);
}

sort($dirFiles);
foreach($dirFiles as $file)
{
    echo "<li><a href=\"Images/$file\" class=\"thickbox\" rel=\"gallery\" title=\"$newstring\"><img src=\"Images/Thumbnails/$file\" alt=\"$newstring\" width=\"300\"  </a></li>\n";
}

?>

编辑：这与您所要求的不相关，但您可以通过获取更一般的处理文件扩展名pathinfo（）函数，你不需要硬编码的ext数组然后，您可以删除任何扩展名。

This isn't related to what you're asking, but you could get a more generic handling of file extensions with the pathinfo() function too. You wouldn't need a hard-coded array of extensions then, you could remove any extension.

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