如何使用java压缩文件夹本身 [英] how to zip a folder itself using java

问题描述

假设我有以下目录结构。

  D：\reports\january\ 
  

在一月份里有两个excel文件说A.xls和B.xls。有很多地方已经写了关于如何使用 java.util.zip 压缩文件。但是我想将janages文件夹本身压缩在报告文件夹中，以便报告中会出现一月份和 january.zip 。 （ 这意味着当我解压缩january.zip文件时，我应该获得一月份文件夹 ）。

任何人都可以使用 java.util.zip 为我提供代码。请让我知道这可以通过使用其他库更容易做到。

非常感谢...

解决方案

解决包 java.util.Zip 不需要任何额外的 Jar 文件

只需复制以下代码，并将与 IDE 一起运行 / p>

  //导入所有需要的包
 package general; 
 import java.io.File; 
 import java.io.FileInputStream; 
 import java.io.FileOutputStream; 
 import java.io.IOException; 
 import java.util.ArrayList; 
 import java.util.List; 
 import java.util.zip.ZipEntry; 
 import java.util.zip.ZipOutputStream; 
 
 public class ZipUtils {
 
 private List< String>的fileList; 
 private static final String OUTPUT_ZIP_FILE =Folder.zip; 
 private static final String SOURCE_FOLDER =D：\\Reports; // SourceFolder path 
 
 public ZipUtils（）{
 fileList = new ArrayList<字符串> （）; 
} 
 
 public static void main（String [] args）{
 ZipUtils appZip = new ZipUtils（）; 
 appZip.generateFileList（new File（SOURCE_FOLDER））; 
 appZip.zipIt（OUTPUT_ZIP_FILE）; 
} 
 
 public void zipIt（String zipFile）{
 byte [] buffer = new byte [1024]; 
 String source = new File（SOURCE_FOLDER）.getName（）; 
 FileOutputStream fos = null; 
 ZipOutputStream zos = null; 
 try {
 fos = new FileOutputStream（zipFile）; 
 zos = new ZipOutputStream（fos）; 
 
 System.out.println（Output to Zip：+ zipFile）; 
 FileInputStream in = null; 
 
（String file：this.fileList）{
 System.out.println（File Added：+ file）; 
 ZipEntry ze = new ZipEntry（source + File.separator + file）; 
 zos.putNextEntry（ze）; 
尝试{
 in = new FileInputStream（SOURCE_FOLDER + File.separator + file）; 
 int len; 
 while（（len = in .read（buffer））> 0）{
 zos.write（buffer，0，len）; 
} 
} finally {
 in.close（）; 
} 
} 
 
 zos.closeEntry（）; 
 System.out.println（Folder successfully compressed）; 
 
} catch（IOException ex）{
 ex.printStackTrace（）; 
} finally {
 try {
 zos.close（）; 
} catch（IOException e）{
 e.printStackTrace（）; 
} 
} 
} 
 
 public void generateFileList（File node）{
 //仅添加文件
 if（node.isFile ））{
 fileList.add（generateZipEntry（node.toString（）））; 
} 
 
 if（node.isDirectory（））{
 String [] subNote = node.list（）; 
 for（String filename：subNote）{
 generateFileList（new File（node，filename））; 
} 
} 
} 
 
 private String generateZipEntry（String file）{
 return file.substring（SOURCE_FOLDER.length（）+ 1，file。长度（））; 
} 
} 
  

参考 mkyong ..i改变了当前问题要求的代码

Suppose I have the following directory structure.

D:\reports\january\

Inside january there are suppose two excel files say A.xls and B.xls. There are many places where it has been written about how to zip files using java.util.zip. But I want to zip the january folder itself inside reports folder so that both january and january.zip will be present inside reports. (That means when I unzip the january.zip file I should get the january folder).

Can anyone please provide me the code to do this using java.util.zip. Please let me know whether this can be more easily done by using other libraries.

Thanks a lot...

解决方案

It can be easily solved by package java.util.Zip no need any extra Jar files

Just copy the following code and run it with your IDE

    //Import all needed packages
package general;
import java.io.File;
import java.io.FileInputStream;
import java.io.FileOutputStream;
import java.io.IOException;
import java.util.ArrayList;
import java.util.List;
import java.util.zip.ZipEntry;
import java.util.zip.ZipOutputStream;

public class ZipUtils {

    private List <String> fileList;
    private static final String OUTPUT_ZIP_FILE = "Folder.zip";
    private static final String SOURCE_FOLDER = "D:\\Reports"; // SourceFolder path

    public ZipUtils() {
        fileList = new ArrayList < String > ();
    }

    public static void main(String[] args) {
        ZipUtils appZip = new ZipUtils();
        appZip.generateFileList(new File(SOURCE_FOLDER));
        appZip.zipIt(OUTPUT_ZIP_FILE);
    }

    public void zipIt(String zipFile) {
        byte[] buffer = new byte[1024];
        String source = new File(SOURCE_FOLDER).getName();
        FileOutputStream fos = null;
        ZipOutputStream zos = null;
        try {
            fos = new FileOutputStream(zipFile);
            zos = new ZipOutputStream(fos);

            System.out.println("Output to Zip : " + zipFile);
            FileInputStream in = null;

            for (String file: this.fileList) {
                System.out.println("File Added : " + file);
                ZipEntry ze = new ZipEntry(source + File.separator + file);
                zos.putNextEntry(ze);
                try {
                    in = new FileInputStream(SOURCE_FOLDER + File.separator + file);
                    int len;
                    while ((len = in .read(buffer)) > 0) {
                        zos.write(buffer, 0, len);
                    }
                } finally {
                    in.close();
                }
            }

            zos.closeEntry();
            System.out.println("Folder successfully compressed");

        } catch (IOException ex) {
            ex.printStackTrace();
        } finally {
            try {
                zos.close();
            } catch (IOException e) {
                e.printStackTrace();
            }
        }
    }

    public void generateFileList(File node) {
        // add file only
        if (node.isFile()) {
            fileList.add(generateZipEntry(node.toString()));
        }

        if (node.isDirectory()) {
            String[] subNote = node.list();
            for (String filename: subNote) {
                generateFileList(new File(node, filename));
            }
        }
    }

    private String generateZipEntry(String file) {
        return file.substring(SOURCE_FOLDER.length() + 1, file.length());
    }
}

Refer mkyong..i changed the code for the requirement of current question

这篇关于如何使用java压缩文件夹本身的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！