如何在与其可执行文件相同的文件夹中启动一个进程 [英] How to start a process in the same folder as its executable

问题描述

我正在尝试以程序方式启动应用程序，但它总是在我的应用程序的文件夹中运行...例如：

I'm trying to start an application programatically, but it always runs it in the folder of my application... For example:

如果我的应用程序位于在C：\MyApp\myapp.exe中，另一个应用程序在C：\OtherApp\otherapp.exe中，如何在其所在的文件夹中启动其他应用程序，而不是在我的应用程序驻留？

If my app is located in C:\MyApp\myapp.exe and the other app is in C:\OtherApp\otherapp.exe, how can I start the other app in the folder in which it resides, rather than in the folder where my app resides?

这是我如何启动其他应用程序：

Here is how I start the other app:

private void StartApp(OtherApp application)
{
    Process process = new Process();
    process.StartInfo.FileName = application.FileName;
    process.StartInfo.Arguments = application.AppName;
    process.Start();
}

推荐答案

我想你的意思是href =http://msdn.microsoft.com/en-us/library/system.diagnostics.processstartinfo.workingdirectory.aspx =noreferrer> ProcessStartInfo.WorkingDirectory属性

I guess you mean ProcessStartInfo.WorkingDirectory Property

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