Java：看目录来移动大文件 [英] Java: Watching a directory to move large files

问题描述

我一直在编写一个程序来监视一个目录，当文件被创建时，它会改变名字并将它们移动到一个新的目录。在我的第一个实现中，我使用Java的Watch Service API，当我测试1kb文件时，它的工作正常。出现的问题是，实际上，创建的文件可以在50-300mb之间。当这种情况发生时，观察者API会立即找到该文件，但由于仍然被写入而无法移动它。我试着把观察者放在一个循环中（生成异常，直到文件可以移动），但是这似乎效率很低。

既然没有工作，我试过了使用定时器，每10秒检查一次文件夹，然后移动文件即可。这是我结束的方法。

问题：无论如何，当文件完成时，无需进行异常检查或持续比较大小？我喜欢为每个文件使用Watcher API一次的想法，而不是使用定时器持续检查（并运行到异常）。

所有的响应都非常感谢！ / p>

nt

解决方案

写另一个文件表示原始文件完成了。
I.g'fileorg.dat'如果完成创建一个文件'fileorg.done'，并且只为'fileorg.done'检查
，就会增长。

使用巧妙的命名约定，您不应该有问题。

I have been writing a program that watches a directory and when files are created in it, it changes the name and moves them to a new directory. In my first implementation I used Java's Watch Service API which worked fine when I was testing 1kb files. The problem that came up is that in reality the files getting created are anywhere from 50-300mb. When this happened the watcher API would find the file right away but could not move it because it was still being written. I tried putting the watcher in a loop (which generated exceptions until the file could be moved) but this seemed pretty inefficient.

Since that didn't work, I tried up using a timer that checks the folder every 10s and then moves files when it can. This is the method I ended up going for.

Question: Is there anyway to signal when a file is done being written without doing an exception check or continually comparing the size? I like the idea of using the Watcher API just once for each file instead of continually checking with a timer (and running into exceptions).

All responses are greatly appreciated!

nt

解决方案

Write another file as an indication that the original file is completed. I.g 'fileorg.dat' is growing if done create a file 'fileorg.done' and check only for the 'fileorg.done'.

With clever naming conventions you should not have problems.

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