JSF：超链接到/ webapp子目录中的网页 [英] JSF: Hyperlink to webpage in /webapp subdirectory

问题描述

我有一个列在我的/ src / main / webapp / pages /文件夹中的.xhtml页面。
现在我想为它们创建超链接。目前，唯一可用的是默认主页：/src/main/webapp/pages/default.xhtml。

I have a list of .xhtml pages that I keep in my /src/main/webapp/pages/ folder. Now I want to create hyperlinks to them. Currently the only one that works is the default home page: /src/main/webapp/pages/default.xhtml.

  <!-- Welcome page -->
  <welcome-file-list>
    <welcome-file>/pages/default.xhtml</welcome-file>
  </welcome-file-list>

  <!-- JSF mapping -->
  <servlet>
    <servlet-name>Faces Servlet</servlet-name>
    <servlet-class>javax.faces.webapp.FacesServlet</servlet-class>
    <load-on-startup>1</load-on-startup>
  </servlet>

  <!-- Map these files with JSF -->
  <servlet-mapping>
    <servlet-name>Faces Servlet</servlet-name>
    <url-pattern>*.jsf</url-pattern>
  </servlet-mapping>
  <servlet-mapping>
    <servlet-name>Faces Servlet</servlet-name>
    <url-pattern>*.xhtml</url-pattern>
  </servlet-mapping>

对于其他人，如果我有一个链接，例如：

For the others, if I have a link such as:

<a href="/pages/page1.xhtml">Page 1</a>

我收到以下错误：

/page1.xhtml在
中找不到外部资源作为资源

/page1.xhtml Not Found in ExternalContext as a Resource

我的问题是：我相对于web应用程序指定了一个href 中的页面。

My question is: How do I specify the page I want in a href relative to the webapp root.

推荐答案

你需要知道的关于相对链接的事情（即不是以http：//开头的）：

Two major things you need to know about relative links (i.e. the ones not starting with http://):

• 相对于域根。


• 没有前导斜杠的相对链接与请求URL相关（因为它在浏览器地址中bar）

如果当前的URL是 http://example.com/app ，该页面包含一个链接

If the current URL is http://example.com/app and the page contains a link

<a href="/pages/page1.xhtml">

那么它将指向 http://example.com/pages/page1.xhtml （failed）。

then it will point to http://example.com/pages/page1.xhtml (fails).

如果当前网址是 http://example.com/app 和页面包含一个链接

If the current URL is http://example.com/app and the page contains a link

<a href="pages/page1.xhtml">

然后它将指向 http://example.com/app/pages/page1.xhtml （作品）。

then it will point to http://example.com/app/pages/page1.xhtml (works).

如果当前网址为 http：// example。 com / app / pages / default.xhtml ，该页面包含一个链接

If the current URL is http://example.com/app/pages/default.xhtml and the page contains a link

<a href="pages/page1.xhtml">

然后它将指向 http://example.com/app/pages/pages/page1.xhtml （failed）。

then it will point to http://example.com/app/pages/pages/page1.xhtml (fails).

您的问题是欢迎页面是由前进而不是重定向打开的。这样，浏览器地址栏中的请求网址就会保留在 http://example.com/app 上它实际上显示了 http://example.com/app/pages/default.xhtml的内容。要在所有情况下使链接都可以工作，您需要像

Your problem is that the welcome page is opened by a forward rather than a redirect. This way the request URL as it is in browser address bar stays on http://example.com/app while it is actually displaying the content of http://example.com/app/pages/default.xhtml. To get the links to work in all circumstances you want a link like

<a href="/app/pages/page1.xhtml">

因此，包括上下文路径，哪个是webapp根。如果您唯一的问题是您想要动态地包含上下文路径，那么只需打印 HttpServletRequest＃getContextPath（）

Thus, including the context path, which is the webapp root. If your sole problem is that you want to include the context path dynamically, then just print HttpServletRequest#getContextPath()

<a href="#{request.contextPath}/pages/page1.xhtml">

另请参见：

• 如何使用没有包括上下文根名称？



See also:

• How to use relative paths without including the context root name?

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