使用Django和Python创建JSON响应 [英] Creating a JSON response using Django and Python
问题描述
我正在尝试将服务器端的Ajax响应脚本转换为Django HttpResponse,但显然它不起作用。
这是服务器端脚本: / p>
/ *接收值* /
$ validateValue = $ _ POST ['validateValue'];
$ validateId = $ _ POST ['validateId'];
$ validateError = $ _ POST ['validateError'];
/ *返回值* /
$ arrayToJs = array();
$ arrayToJs [0] = $ validateId;
$ arrayToJs [1] = $ validateError;
if($ validateValue ==Testuser){//验证?
$ arrayToJs [2] =true; // RETURN TRUE
echo'{jsonValidateReturn:'。json_encode($ arrayToJs)。'}'; //返回阵列成功
}
else {
($ x = 0; $ x <1000000; $ x ++){
if($ x == 990000){
$ arrayToJs [2] =false;
echo'{jsonValidateReturn:'。json_encode($ arrayToJs)。'}'; // RETURBS ARRAY WITH ERROR。
}
}
}
这是转换后的代码
def validate_user(request):
如果request.method =='POST':
vld_value = request.POST.get('validateValue')
vld_id = request.POST.get('validateId')
vld_error = request.POST.get('validateError')
array_to_js = [vld_id,vld_error,False]
如果vld_value ==TestUser:
array_to_js [2] = True
x = simplejson.dumps(array_to_js)
返回HttpResponse(x)
else:
array_to_js [2] = False
x = simplejson.dumps(array_to_js)
error ='Error'
return render_to_response('index .html',{'error':error},context_instance = RequestContext(request))
return render_to_response('index.html',context_instance = RequestContext(request))
我使用simplejson对Python列表进行编码(因此它将返回一个JSON数组)。我找不到问题。但是我觉得我对'echo'做了一些错误。
我通常使用一个字典而不是列表返回JSON内容
import json
from django.http import HttpResponse
response_data = {}
response_data ['result'] ='error'
response_data ['message'] ='一些错误消息'
前Django 1.7你会这样返回:
return HttpResponse json.dumps(response_data),content_type =application / json)
对于Django 1.7+,使用 JsonResponse
,如此SO答案所示:
django.http import JsonResponse
return JsonResponse({'foo':'bar'})
$ p
$ p>I'm trying to convert a server side Ajax response script into a Django HttpResponse, but apparently it's not working.
This is the server-side script:
/* RECEIVE VALUE */ $validateValue=$_POST['validateValue']; $validateId=$_POST['validateId']; $validateError=$_POST['validateError']; /* RETURN VALUE */ $arrayToJs = array(); $arrayToJs[0] = $validateId; $arrayToJs[1] = $validateError; if($validateValue =="Testuser"){ // Validate?? $arrayToJs[2] = "true"; // RETURN TRUE echo '{"jsonValidateReturn":'.json_encode($arrayToJs).'}'; // RETURN ARRAY WITH success } else{ for($x=0;$x<1000000;$x++){ if($x == 990000){ $arrayToJs[2] = "false"; echo '{"jsonValidateReturn":'.json_encode($arrayToJs).'}'; // RETURNS ARRAY WITH ERROR. } } }
And this is the converted code
def validate_user(request): if request.method == 'POST': vld_value = request.POST.get('validateValue') vld_id = request.POST.get('validateId') vld_error = request.POST.get('validateError') array_to_js = [vld_id, vld_error, False] if vld_value == "TestUser": array_to_js[2] = True x = simplejson.dumps(array_to_js) return HttpResponse(x) else: array_to_js[2] = False x = simplejson.dumps(array_to_js) error = 'Error' return render_to_response('index.html',{'error':error},context_instance=RequestContext(request)) return render_to_response('index.html',context_instance=RequestContext(request))
I'm using simplejson to encode the Python list (so it will return a JSON array). I couldn't figure out the problem yet. But I think that I did something wrong about the 'echo'.
解决方案I usually use a dictionary, not a list to return JSON content.
import json from django.http import HttpResponse response_data = {} response_data['result'] = 'error' response_data['message'] = 'Some error message'
Pre-Django 1.7 you'd return it like this:
return HttpResponse(json.dumps(response_data), content_type="application/json")
For Django 1.7+, use
JsonResponse
as shown in this SO answer like so :from django.http import JsonResponse return JsonResponse({'foo':'bar'})
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