如何使用基于Django类的通用ListView分页? [英] How do I use pagination with Django class based generic ListViews?

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问题描述

如何在Django 1.3中使用分页?

How do I use pagination with Django 1.3?

文件不是很清楚。


  • 什么去我的 views.py

我的模板是什么?

我的URLconf文件有哪些?

What goes to my URLconf file?

推荐答案

我想你要求有关使用分页的新视图的信息,因为使用传统的基于功能的视图,很容易找到。我发现只要设置 paginate_by 变量就足以激活分页。请参阅 基于类的通用视图

I think you ask for information about using pagination with the new class based views since, with traditional function based views, it is easy to find. I found that just by setting the paginate_by variable is enough to activate the pagination. See in Class-based generic views.

例如,在视图中。 py

import models
from django.views.generic import ListView

class CarListView(ListView):
    model = models.Car      # shorthand for setting queryset = models.Car.objects.all()
    template_name = 'app/car_list.html'  # optional (the default is app_name/modelNameInLowerCase_list.html; which will look into your templates folder for that path and file)
    context_object_name = "car_list"    #default is object_list as well as model's_verbose_name_list and/or model's_verbose_name_plural_list, if defined in the model's inner Meta class
    paginate_by = 10  #and that's it !!

在您的模板( car_list.html )您可以包含这样的分页部分(我们有一些上下文变量可用: is_paginated page_obj paginator )。

In your template (car_list.html), you can include a pagination section like this (we have some context variables available: is_paginated, page_obj, and paginator).

{# .... **Normal content list, maybe a table** .... #}
{% if car_list %}
    <table id="cars">
        {% for car in car_list %}
            <tr>
                <td>{{ car.model }}</td>
                <td>{{ car.year }}</td>
                <td><a href="/car/{{ car.id }}/" class="see_detail">detail</a></td>
            </tr>
        {% endfor %}
    </table>
    {# .... **Now the pagination section** .... #}
    {% if is_paginated %}
        <div class="pagination">
            <span class="page-links">
                {% if page_obj.has_previous %}
                    <a href="/cars?page={{ page_obj.previous_page_number }}">previous</a>
                {% endif %}
                <span class="page-current">
                    Page {{ page_obj.number }} of {{ page_obj.paginator.num_pages }}.
                </span>
                {% if page_obj.has_next %}
                    <a href="/cars?page={{ page_obj.next_page_number }}">next</a>
                {% endif %}
            </span>
        </div>
    {% endif %}
{% else %}
    <h3>My Cars</h3>
    <p>No cars found!!! :(</p>
{% endif %}
{# .... **More content, footer, etc.** .... #}

要显示的页面由GET参数指示,只需添加?page = n ,到URL。

The page to display is indicated by a GET parameter, simply adding ?page=n, to the URL.

这篇关于如何使用基于Django类的通用ListView分页?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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